Not sure if I did this properly... Section II: ProblemsProblem 2: Newton's LawsPage 4A 1.27•kg mass M slides down a plane inclined at an angle e = 55° to the horizontal.There is a 2.66•N frictional force on the mass. Take the x•axis along the plane in thegenerally downward direction and take the y•axis normal to the plane in the generallyupward direction, as shown in the figure.%3D(2) Draw a free body diagram of the mass. Be sure to label all forces clearly and toplace the angle e in your diagram.mgy =mgsin 55.moy =mgcos5s.0 = FN-mgyO = FM-mgcos55FN=mg cus55m= 1.27kgO = 55°(b) Find the acceleration of the mass M down the plane in the x•direction.mgx=maigsins5 = magsin55 = aa-8.04 misz- Ff%3D%3D5.38m/5²ax=a= 5.38MIs2(c) What is the acceleration of the mass M in the y•direction? Explain your answer.%3D9u COS55 = aay=_ 5,63m/s 2a =5,63 m/sO Find the magnitude of the normal force acting on the mass May =FN=mgcos55FN = (1.27kg)(9.81mis)(cos(55))FM=7.15M7.15 Nn =(e) Find the coefficient of kinetic friction between the mass and the plane.yigsine-Mygcose = rhaI (sine -MCOSB)=xM ="a+9sinA M=4.6?CoseHk =

The mistake you made is : The direction of x axis is down the plank and y axis is perpendicualr to…

Problem 2: Newton's Laws M A 1.27-kg mass M slides down a plane inclined at an angle e = 55° to the horizontal. There is a 2.66•N frictional force on the mass. Take the x•axis along the plane in the generally downward direction and take the y•axis normal to the plane in the generally upward direction, as shown in the figure. (a) Draw a free body diagram of the mass. Be sure to label all forces clearly and to place the angle 0 in your diagram. mgy =mgsin 55. mgy =mgcos550 0 = FN-mgy O = FM-mgcos5s FN =mg cos55 m = \.27kg O = 55° (b) Find the acceleration of the mass M down the plane in the x•direction. mgx: mgsins5= ma gsin55 = a a-8.04 misz- FF =ma 5.38m/s² ax= a= 5.38M/s2 (C) What is the acceleration of the mass M in the y•direction? Explain your answer. a =5,63 m/s 2 (d) Find the magnitude of the normal force acting on the mass M . 9, COS55 = a ay = 2 5,63 m/s FN=mgcos55 FN = (1.27kg)(9.81mis) (cos(55)) FM=7,15N 7.15N n = (e) Find the coefficient of kinetic friction between the mass and the plane. yhgsine-Myg coso = vha I (sine -MOSB)=ax M ="a+gsin M-4.6? Cose Hk=

Problem 2: Newton's Laws M A 1.27-kg mass M slides down a plane inclined at an angle e = 55° to the horizontal. There is a 2.66•N frictional force on the mass. Take the x•axis along the plane in the generally downward direction and take the y•axis normal to the plane in the generally upward direction, as shown in the figure. (a) Draw a free body diagram of the mass. Be sure to label all forces clearly and to place the angle 0 in your diagram. mgy =mgsin 55. mgy =mgcos550 0 = FN-mgy O = FM-mgcos5s FN =mg cos55 m = \.27kg O = 55° (b) Find the acceleration of the mass M down the plane in the x•direction. mgx: mgsins5= ma gsin55 = a a-8.04 misz- FF =ma 5.38m/s² ax= a= 5.38M/s2 (C) What is the acceleration of the mass M in the y•direction? Explain your answer. a =5,63 m/s 2 (d) Find the magnitude of the normal force acting on the mass M . 9, COS55 = a ay = 2 5,63 m/s FN=mgcos55 FN = (1.27kg)(9.81mis) (cos(55)) FM=7,15N 7.15N n = (e) Find the coefficient of kinetic friction between the mass and the plane. yhgsine-Myg coso = vha I (sine -MOSB)=ax M ="a+gsin M-4.6? Cose Hk=

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter9: Energy In Nonisolated Systems

Section: Chapter Questions

Problem 1PQ: Pick an isolated system for the following scenarios while including the fewest number of objects as...

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