Problem 3 The two children shown in the figure are balanced on a seesaw of mass M = The center of mass of the seesaw is 0.160 m to the left 12 kg. of the pivot (on the side of the lighter child). The first child (on the left) has a mass of m1 = 26.0 kg and sits a distance of ri = 1.60 m from the pivot. If the second child has a mass of m2 = 32.0 kg, how far is she from the pivot? m, F, m2 W2 Be sure to explicitly follow the problem solving process taught in class this semester [(a) interpret problem, (b) choose the appropriate equation(s), (c) algebraically solve for the unknown in terms of known variables (this is the "symbolic solution"), (d) substitute numbers (with units) into the symbolic solution, and (e) calculate the final numeric solutions with appropriate units and significant figures ).
Problem 3 The two children shown in the figure are balanced on a seesaw of mass M = The center of mass of the seesaw is 0.160 m to the left 12 kg. of the pivot (on the side of the lighter child). The first child (on the left) has a mass of m1 = 26.0 kg and sits a distance of ri = 1.60 m from the pivot. If the second child has a mass of m2 = 32.0 kg, how far is she from the pivot? m, F, m2 W2 Be sure to explicitly follow the problem solving process taught in class this semester [(a) interpret problem, (b) choose the appropriate equation(s), (c) algebraically solve for the unknown in terms of known variables (this is the "symbolic solution"), (d) substitute numbers (with units) into the symbolic solution, and (e) calculate the final numeric solutions with appropriate units and significant figures ).
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter9: Statics And Torque
Section: Chapter Questions
Problem 5PE: Repeat the seesaw problem in Example 9.1 with the center of mass of the seesaw 0.160 m to the left...
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