Problem 5: A cube, centered on the origin, with sides that are parallel to the x-y, y-z, and x-z planes and have an edge length of L, is immersed in an electric field given by E(x) = Eo(ar'i+ 2j + 5k). Refer to the figure. X Part (a) Integrate to find an expression for the total electric flux through the cube in terms of defined quantities and enter the expression. 'a Part (b) If L = 6.3 m, a = 0.75 m3, and Eo = 69 V/m, what is the value of the flux, in units of volt•meter? Pa Part (c) If the electric field is E(x) = E0(Bx²i+ 2j + 15k) with B= 2.5, what is the value of the flux, in units of volt meter?

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Chapter25: Gauss’s Law
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P5E5

Problem 5: Acube, centered on the origin, with sides that are parallel to the x-y, y-z, and x-z
planes and have an edge length of L, is immersed in an electric field given by E(x) = Eo(ar'i+ 2j +
5k). Refer to the figure.
X
Z
Part (a) Integrate to find an expression for the total electric flux through the cube in terms of defined quantities and enter the expression.
Фа
Part (b) If L = 6.3 m, a = 0.75 m, and E, = 69 V/m , what is the value of the flux, in units of volt•meter?
Pa
Part (c) If the electric field is E(x)= Eo(ßx²i+ 2j + 15k) with B = 2.5, what is the value of the flux, in units of volt•meter?
Transcribed Image Text:Problem 5: Acube, centered on the origin, with sides that are parallel to the x-y, y-z, and x-z planes and have an edge length of L, is immersed in an electric field given by E(x) = Eo(ar'i+ 2j + 5k). Refer to the figure. X Z Part (a) Integrate to find an expression for the total electric flux through the cube in terms of defined quantities and enter the expression. Фа Part (b) If L = 6.3 m, a = 0.75 m, and E, = 69 V/m , what is the value of the flux, in units of volt•meter? Pa Part (c) If the electric field is E(x)= Eo(ßx²i+ 2j + 15k) with B = 2.5, what is the value of the flux, in units of volt•meter?
Expert Solution
Step 1

The electric flux through a surface can be defined as the total number of electric field lines passing through a surface of area. The electric flux through an elemental area, dA, can expressed by the following,

dφ=E·dA          (1)

Here, dφ is the electric flux and E is the electric field. Area is also a vector whose direction is perpendicular to the surface. Therefore the flux is the product of the perpendicular component of the electric field and the area of the surface.

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