Problem 9:A capacitor is charged with a total charge of q = 5.1E-05 C. The capacitor is wired in series with a resistor, R-8Randomized Variablesq = 5.1 E-05 C← Δ Part (a) Input an expression for the time constant, τ, of this circuit using the variablesprovided and C for capacitance.HOME4 5 6BACKSCLEARSubmitHintI give up!Hints: 1 -deduction per hint. Hints remaining:Feedback:deduction per feedback.Part (b) What is the value of the time constant in s if the capacitor has capacitance of1.0 μF?ΔPart (c) How long will it take the capacitor to discharge half of its charge in seconds?

(a)The expression for time constant is,

Answered: Problem 9: A capacitor is charged with…

University Physics Volume 2

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ISBN:9781938168161

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Chapter10: Direct-current Circuits

Section: Chapter Questions

Problem 55P: An ECG monitor must have an KC time constant lessthan 1.00102s to be able to measure variations...

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A capacitor with initial charge Q0 is connected across a resistor R at time t = 0. The separation between the plates of the capacitor changes as d = d0/(1 + t) for 0 t 1 s. Find an expression for the voltage drop across the capacitor as a function of time.
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Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?
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Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage Vout from a source voltage . Determine the required value of R2 if = 5.00 V, Vout = 1.50 V and R1 = 1.00 103 (Hint: Use Kirchhoff's loop rule, substituting Vout = IR2, to find the current. Then solve Ohms law for R2. Figure P18.26
An ECG monitor must have an KC time constant lessthan 1.00102s to be able to measure variations involtage oversmall time intervals, (a) If the resistance of the circuit (duemostly to that of the patient's chest) is 1.00kTwhat is the maximum capacitance of the circuit?(b) Would It be difficult in practice to limit the capacitance to less than the value found in (a)?
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