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- A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?Consider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source whose voltage is e1(t)=100(1| t |)volts for 1t1ande1(t)=0 for | t |1 second. A2- farad capacitor is connected across winding 2. Sketch e1(t),e2(t),i1(t),andi2(t) versus time t.An autotransformer is used to transform from 500 to 440V. The load is 20kW, at unity pf. Neglecting losses and magnetizing current, find the current in the common winding.
- The diagram shown below is a typical tuning circuit. Considering this circuit comprises a transformer (with a coil ratio of 20:1 and an HV side voltage of 240V ), a capacitor of impedance -j20Ω, an inductor of impedance j40Ω, and a 50Ω resistor, determine: the current supplied by the source (0.2228) the impedance seen at the supply (HV side)(21540.55) the power dissipated by the resistor(2.482 watts) the operating power factor of the fitting(0.928 lagging) If the capacitor is now removed from the above circuit and is placed in parallel with the secondary of the transformer, redraw the circuit diagram and recalculate parts a. to d. in question (i). Draw the phasor diagram for both series and parallel RLC circuits in parts (i) and (ii). Discuss the effects of changing the capacitor connection in parallel on the power factor of the circuit. State the benefits of using the transformer in the above circuit. Explain the operating principle of the transformer with particular reference to…Consider a transformer with a primary coil consisting of 1490 turns and a secondary coil of 1900 turns. An alternating RMS voltage 232.5 V is applied to the primary coil, and the output RMS voltage 48 V is measured across the load resistor of resistance 114.5 Ohm connected to the secondary coil. What is the internal resistance of the secondary coil?The diagram shown below is a typical tuning circuit. Considering this circuit comprises a transformer (with a coil ratio of 20:1 and an HV side voltage of 240V ), a capacitor of impedance -j20Ω, an inductor of impedance j40Ω, and a 50Ω resistor, determine: the current supplied by the source the impedance seen at the supply (HV side) the power dissipated by the resistor the operating power factor of the fitting If the capacitor is now removed from the above circuit and is placed in parallel with the secondary of the transformer, redraw the circuit diagram and recalculate parts a. to d. in question (i). Draw the phasor diagram for both series and parallel RLC circuits in parts (i) and (ii). Discuss the effects of changing the capacitor connection in parallel on the power factor of the circuit. State the benefits of using the transformer in the above circuit. Explain the operating principle of the transformer with particular reference to electro-magnetic…
- A coil has resistance of 5 ohm and capacitive reactance of 6 ohm . a) what is the impedance of the coil? b) what is the admittance of the coil?A coil has resistance of 5 ohm and inductive reactance of 4 ohm. a) what is the impedance of the coil? b) what is the admittance of the coil?An Impedance Coil has a resistance of 7.5 ohms and an inductive reactance of 18 ohms (connected in series). a) What is the voltage equation for a voltage that produces a current i = 11.3sinwt, b) Solve for the values of E, I, voltage across the resistor and voltage across the inductor.
- 1) For the BOOST converter, a DC 50 Volt DC voltage of B Volt is taken into an A ohm load. If inductance current is continuous and operating frequency is 10 Khzc : 100UF ;(30) a) Draw the circuit diagram b) Find the work rate c)Find the minimum required inductance value d) Find the Imin and Imax valuee) Find the power consumed by the loadQuestion 1. An industrial load consisting of a set of induction motors connected to a 220 V, 60 Hz single phase source consumes 50 kW with a back power factor of 0.8. The power factor will be increased back to 0.95 by connecting a set of capacitors in parallel. For this, calculate the VA value that the connected capacitor will provide.Two coupled coils of L1=0.8 H and L2=0.2 H have a coupling coefficient K=0.8. What will their mutual inductance ?