Procopio is driving a car (m = 1000 kg) at v1 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: W = By the work-energy theorem: W = - K1 = -2 Combining these two equations for work and isolating F, we obtain an expression for F: F = 2/( Plugging in values, we know that 4.4 newtons of force is needed to stop the car.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter7: Energy Of A System
Section: Chapter Questions
Problem 7.3OQ: A worker pushes a wheelbarrow with a horizontal force of 50 N on level ground over a distance of 5.0...
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Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a
distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car?
The work done by the force F as the car traveled a distance s before stopping is:
W =
By the work-energy theorem:
W =
- K1 = -½
Combining these two equations for work and isolating F, we obtain an expression for F:
F =
2/0
Plugging in values, we know that
4.4 newtons of force is needed to stop the car.
Transcribed Image Text:Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force F as the car traveled a distance s before stopping is: W = By the work-energy theorem: W = - K1 = -½ Combining these two equations for work and isolating F, we obtain an expression for F: F = 2/0 Plugging in values, we know that 4.4 newtons of force is needed to stop the car.
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