Procopio is driving a car (m = 1000 kg) at vj = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: W = By the work-energy theorem: 2 W = - K1 = -½ Combining these two equations for work and isolating F, we obtain an expression for F: F= 2/1 Plugging in values, we know that 4.4 newtons of force is needed to stop the car.

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter6: Energy Of A System
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Expression your answers without rounding off and without scientific notaiton; Fill in the blanks

Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force F was needed to stop the car?
The work done by the force Fas the car traveled a distance s before stopping is:
W =
By the work-energy theorem:
2
W =
- K1 = -½
Combining these two equations for work and isolating F, we obtain an expression for F:
F =
2/
Plugging in values, we know that
4.4 newtons of force is needed to stop the car.
Transcribed Image Text:Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force F was needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: W = By the work-energy theorem: 2 W = - K1 = -½ Combining these two equations for work and isolating F, we obtain an expression for F: F = 2/ Plugging in values, we know that 4.4 newtons of force is needed to stop the car.
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