Procopio is driving a car (m = 1000 kg) at v7 - 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: w- Fs By the work-energy theorem: w- K2 - K1 --2 m v1 Combining these two equations for work and isolating F, we obtain an expression for F: F- -1/2m 2( s V1 Plugging in values, we know that -411 4.4 newtons of force is needed to stop the car.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter7: Energy Of A System
Section: Chapter Questions
Problem 7.3OQ: A worker pushes a wheelbarrow with a horizontal force of 50 N on level ground over a distance of 5.0...
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Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m
before stopping completely. How much force Fwas needed to stop the car?
The work done by the force Fas the car traveled a distance s before stopping is:
W = Fs
By the work-energy theorem:
w = K2
|- K1 = -2 m
v1
Combining these two equations for work and isolating F, we obtain an expression for F:
F= -1/2m
2(S
V1
Plugging in values, we know that -411
4.4 newtons of force is needed to stop the car.
2.
Transcribed Image Text:Procopio is driving a car (m = 1000 kg) at v7 = 11.11 m/s when he stepped on the brakes. The car traveled a distance of s = 15 m before stopping completely. How much force Fwas needed to stop the car? The work done by the force Fas the car traveled a distance s before stopping is: W = Fs By the work-energy theorem: w = K2 |- K1 = -2 m v1 Combining these two equations for work and isolating F, we obtain an expression for F: F= -1/2m 2(S V1 Plugging in values, we know that -411 4.4 newtons of force is needed to stop the car. 2.
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