A force F = 3i + 7j + 7k acts on a 2 kg mobile object that moves from an initial position of D1 = 3i – 2j + 5k to a final position D2 = - 5i + 4j + 7k in 4 seconds. What is the average power due to the force during that 4 s interval? -

University Physics Volume 1
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Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 37P: Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an...
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A force F = 3i + 7j + 7k acts on a 2 kg mobile object that moves from an initial
position of D1
D2 =
the force during that 4 s interval?
3i – 2j + 5k to a final position
-5i + 4j + 7k in 4 seconds. What is the average power due to
20 W
20 J
O1 W
8 W
O 13 W
Transcribed Image Text:A force F = 3i + 7j + 7k acts on a 2 kg mobile object that moves from an initial position of D1 D2 = the force during that 4 s interval? 3i – 2j + 5k to a final position -5i + 4j + 7k in 4 seconds. What is the average power due to 20 W 20 J O1 W 8 W O 13 W
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