Proportional Relationships in Chemical Reactions A chemist runs three trials of an experiment to produce ammonia (NH3) from nitrogen (N₂) and hydrogen (H₂). The unbalanced equation is I N₂ + H₂ ->> NH3 The chemist places different amounts of the reactants in a reaction vessel, adjusts some of the conditions such as pressure and temperature, and then records the amounts of the reactants and the products in the table. Amount of Products and Reactants for N₂ + H₂ → NH3 Trial Original amount (mol) Final amount (mol) Change in amount (mol) H₂ NH3 N₂ H₂ NH3 N₂ H₂ NH3 N₂ 0.345 0.345 0.000 1 0.335 0.315 0.020 2 0.102 0.345 0.000 0.032 0.135 0.140 3 0.345 0.298 0.000 0.305 0.178 0.080 1. SEP Use Mathematics Calculate (in moles) the amount of each reactant that was used up in the reaction and the amount of product that was produced. Record your answers in the table.

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Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.128QP
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ding 1
11
Arial
TE
GO
B I U A
34
12.
5
1
Proportional Relationships in Chemical
Reactions
A chemist runs three trials of an experiment to produce ammonia (NH3) from nitrogen
(N₂) and hydrogen (H₂). The unbalanced equation is
I
N₂ + H₂ → NH3
The chemist places different amounts of the reactants in a reaction vessel, adjusts
some of the conditions such as pressure and temperature, and then records the
amounts of the reactants and the products in the table.
Amount of Products and Reactants for N₂ + H₂ → NH3
Trial
Original amount (mol)
Final amount (mol)
Change in amount
(mol)
N₂
H₂
NH3
N₂ H₂ NH3
N₂
H₂
NH3
1
0.345 0.345
0.000
0.335
0.315
0.020
2
0.102 0.345
0.000 0.032 0.135
0.140
3
0.345 0.298 0.000 0.305 0.178
0.080
1. SEP Use Mathematics Calculate (in moles) the amount of each reactant that
was used up in the reaction and the amount of product that was produced.
Record your answers in the table.
12 +
=X
=
III
E
7
lil
IM
Transcribed Image Text:ding 1 11 Arial TE GO B I U A 34 12. 5 1 Proportional Relationships in Chemical Reactions A chemist runs three trials of an experiment to produce ammonia (NH3) from nitrogen (N₂) and hydrogen (H₂). The unbalanced equation is I N₂ + H₂ → NH3 The chemist places different amounts of the reactants in a reaction vessel, adjusts some of the conditions such as pressure and temperature, and then records the amounts of the reactants and the products in the table. Amount of Products and Reactants for N₂ + H₂ → NH3 Trial Original amount (mol) Final amount (mol) Change in amount (mol) N₂ H₂ NH3 N₂ H₂ NH3 N₂ H₂ NH3 1 0.345 0.345 0.000 0.335 0.315 0.020 2 0.102 0.345 0.000 0.032 0.135 0.140 3 0.345 0.298 0.000 0.305 0.178 0.080 1. SEP Use Mathematics Calculate (in moles) the amount of each reactant that was used up in the reaction and the amount of product that was produced. Record your answers in the table. 12 + =X = III E 7 lil IM
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