Prove that the force generated (per unit depth), F, by a pinnate muscle arrangement is F = 2fl sin æ cos a (8.26) where f is the force generated per unit cross-sectional muscle area, I is the pinnate segment length, and a is the muscle fiber angle.

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter1: Matrices, Vectors, And Vector Calculus
Section: Chapter Questions
Problem 1.6P
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Prove that the force generated (per unit depth), F, by a pinnate muscle
arrangement is
F = 2fl sin æ cos a
(8.26)
where f is the force generated per unit cross-sectional muscle area, I is the
pinnate segment length, and a is the muscle fiber angle.
Transcribed Image Text:Prove that the force generated (per unit depth), F, by a pinnate muscle arrangement is F = 2fl sin æ cos a (8.26) where f is the force generated per unit cross-sectional muscle area, I is the pinnate segment length, and a is the muscle fiber angle.
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