Pyridine N-oxides can also react in electrophilic aromatic substitutions. In the reaction below, only a single product is obtained. Use resonance structures to justify the selective formation of this product. NO2 HNO3 H,SO4
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- Aromatic substitution can be done on naphthalene. Treatment of naphthalene with concentrated H2SO4 gives two (and only two) different sulfonic acids.The compound MON-0585 is a non-toxic, biodegradable larvicide that is highly selective against mosquito larvae. Synthesize MON-0585 using either benzene or phenol as a source of the aromatic rings.1, 6-Methanonaphthalene has an interesting 1H NMR spectrum in which the eight hydrogens around the perimeter absorb at 6.9 to 7.3 δ, while the two CH2 protons absorb at -0.5 δ. Tell whether it is aromatic, and explain its NMR spectrum.
- Give a proposal on the synthesis methods of CoSO4.7H2OStarting with Benzene (or naphthalene or biphenyl) Show a sequence of 3 electrophilic aromatic substitution reactions. And the intermediates and products Each EAS reaction must introduce a different group on the ringElectrophilic aromatic substitution usually occurs at the 1-position of naphthalene, also called the a position. Predict the major products of the reactions of naphthalene with HNO3, H2SO4.
- For the compound p-anisidne 2. Name and draw the structures of all possible chemical (Electrophilic aromatic substitution) reactions of the compound namely; a. Halogenation (Chlorination or Bromination) b. Nitration c. Sulphonation d. Friedal Craft Alkylation e. Friedal Craft Acylation (Their name and their structure)Propose a structure for an aromatic hydrocarbon, C10H14, that can form only one C10H13Cl product on substitution of a hydrogen on the aromatic ring with chlorine.Styrene (vinylbenzene) undergoes electrophilic aromatic substitution much faster thanbenzene, and the products are found to be primarily ortho- and para-substituted styrenes.Use resonance forms of the intermediates to explain these results.
- Describe the ozonolysis of alkenes one mole of a hydrocarbon(A) reacts with one mole of beomine giving a dibromo compound C5H10Br2.Substance A on treatment with cold dilute kMnO4 solution forms a compound C5C12O2(C5H12O2) on ozonolysis A,gives equimolar quantities of propanone and ethanol.Deduce the structure of substance A.Hydrocarbon X has the formula C6H12.X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a product having 12 primary hydrogens.Treatment of X with ozone followed by zinc in aqueous acid gives a mixture two aldehydes.What is the structure of X?The carbocation electrophile in a Friedel-Crafts reaction can be generated in ways other than by reaction of an alkyl chloride with AlCl3. For example, reaction of benzene with 2-methylpropene in the presence of H3PO4 yields tert-butylbenzene. Draw a structure for the electrophile.