Python Using recursion only No loops Using such type()function, len()function, max(), indexing(lst[i]), slicing(lst[i:j]) The function must return the biggest dict in the list and not print   def findMaxLenD(lst):

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Python

Using recursion only

No loops

Using such type()function, len()function, max(), indexing(lst[i]), slicing(lst[i:j])

The function must return the biggest dict in the list and not print

 

def findMaxLenD(lst):

>>> val = findMaxLenD([])
>>> val
>>> val = findMaxLenD([{'JoJo': 5}, [[[[(1,2, 3), 'four', {'LaRue': 10}]]]], [['five']]])
>>> val
1
>>> val = findMaxLenD([[[[{'JoJo': 5, 'test': 1.5}]]], [[[[(1,2, 3), 'four', {'LaRue': 10}]]]], [['five']]])
>>> val
>>> val = findMaxLenD([[[['JOJO']], [[[[(1,2, 3), 'four', {'LaRue': 10, 'one': 1, 'two': 2, 'three': 3}]]]],
[['five', {1,2, 3},{'Annika': 1, 'testing': 2, 'test': 3}]]])
>>> val
4
>>> val = findMaxLenD([[[[{'JOJO': 5, 'test': 1.5}]]], [[[[(1, 2, 3), 'four', {'LaRue': 10}]]]], [['five', {1, 2,
3},{'Annika': 1, 'testing': 2, 'test': 3}]]])
>>> val
3
>>> val =
findMaxLenD([{1,2,3}, [[[[(1,2, 3), 'four', {'LaRue': 10, 'one': 1, 'two': 2, 'three': 3}]]]],
[['five', {1,2,3},'Annika']]])
>>> val
Transcribed Image Text:>>> val = findMaxLenD([]) >>> val >>> val = findMaxLenD([{'JoJo': 5}, [[[[(1,2, 3), 'four', {'LaRue': 10}]]]], [['five']]]) >>> val 1 >>> val = findMaxLenD([[[[{'JoJo': 5, 'test': 1.5}]]], [[[[(1,2, 3), 'four', {'LaRue': 10}]]]], [['five']]]) >>> val >>> val = findMaxLenD([[[['JOJO']], [[[[(1,2, 3), 'four', {'LaRue': 10, 'one': 1, 'two': 2, 'three': 3}]]]], [['five', {1,2, 3},{'Annika': 1, 'testing': 2, 'test': 3}]]]) >>> val 4 >>> val = findMaxLenD([[[[{'JOJO': 5, 'test': 1.5}]]], [[[[(1, 2, 3), 'four', {'LaRue': 10}]]]], [['five', {1, 2, 3},{'Annika': 1, 'testing': 2, 'test': 3}]]]) >>> val 3 >>> val = findMaxLenD([{1,2,3}, [[[[(1,2, 3), 'four', {'LaRue': 10, 'one': 1, 'two': 2, 'three': 3}]]]], [['five', {1,2,3},'Annika']]]) >>> val
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