q. pV = nRT r. sin 0c = n₁ n₂ 1 s. qV= = 2/27 == my ² ‚T= ‚0c = C , V =

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.94QP
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D
q. pV = nRT
n₁
r.
sin e
n₂
1
s. qV:
=
mv ²
2
C
-
‚T =
,0 =
C
, V =
Transcribed Image Text:D q. pV = nRT n₁ r. sin e n₂ 1 s. qV: = mv ² 2 C - ‚T = ,0 = C , V =
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