Q.1. For hypoeutoctoid plain carbon steel (select %C content yourself), determine the phases that are present, the compositions of these phases, and the percentages or fractions of the phases. Make schematic sketches of the microstructure that would be observed for conditions of very slow cooling at the following temperatures: a) Just above the austenite transformation temperature b) The austenite transformation temperature - 10°C c) The eutectoid transformation temperature +10°C d) The eutectoid transformation temperature - 10°C

Q.1. For hypoeutoctoid plain carbon steel (select %C content yourself), determine the phases that are present, the compositions of these phases, and the percentages or fractions of the phases. Make schematic sketches of the microstructure that would be observed for conditions of very slow cooling at the following temperatures: a) Just above the austenite transformation temperature b) The austenite transformation temperature - 10°C c) The eutectoid transformation temperature +10°C d) The eutectoid transformation temperature - 10°C

Precision Machining Technology (MindTap Course List)

2nd Edition

ISBN:9781285444543

Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Chapter2: Measurement, Materials, And Safety

Section2.7: Heat Treatment Of Metals

Problem 2RQ: Direct hardening can be performed on steel containing at least________ carbon.

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Q.1.For hypoeutoctoid plain carbon steel(select %C content yourself), determine the phasesthat are present, the compositionsof these phases, and the percentages or fractionsof the phases.Make schematic sketches of the microstructurethat would be observed for conditions of very slow cooling at the following temperatures: a)Just above the austenite transformation temperature b)The austenite transformation temperature -10C c)The eutectoid transformation temperature +10C d)The eutectoid transformation temperature -10C
The Fe – Au solid – liquid T – xB phase diagram can be viewed as the intersection of asolid – phase miscibility gap with a solid – liquid phase – transition loop having aminimum at xAu = 0.8. The miscibility gap intersects the phase transition loop at xAu =0.1 and at xAu = 0.3. Fe has a higher melting point than Au. Sketch the phase diagramand label all the areas.
1. Given the time-temperature transformation diagram, what would be the phases present for a 1.13 wt. % C steel with no alloying elements. calculate the amount of pro eutectoid product, where applicable (at the bottom) A) quenched in cold water to 650 C in 0.1 seconds, then held at 650 C for 5 seconds, then quenched to 400 C, held at 400C for 60 seconds, and finally quenched to room temperature B. Necessary Steel Phase Diagram Calculations to determine the amount of pro eutectoid product:
Choose the corect answer -A vertical line in the phase diagram represents a.an intermetallic compound b.a eutectic phase c.a eutectoid phase Match each statement with a letter -In the peritectoid reaction -In the Peritectic reaction: -In the Monotectic reaction: -In the Eutectoid reaction: -In the Eutectic reaction: a. a liquid phase transforms into two solids when it is cooled down b. a solid phase transforms into two different solids when it is cooled down c. a liquid phase transforms into a new liquid phase and a solid phase d. Two solid phases transform into a new single solid phase e. A solid phase and a liquid phase transforms into a solid phase
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1. Given the time-temperature transformation diagram, what would be the phases present for a 1.13 wt. % C steel with no alloying elements. part A) quenched in cold water directly to room temperature in 0.1 second part B) quenched in cold water directly to room temperature in 0.1 seconds, then heated to 425 C and held there for 1000 seconds, and finally quenched to room temperature part C) quenched in cold water to 670 C in 0.1 seconds, then held at 670 C for 1000 seconds, then quenched to room temperature part D) quenched in cold water to 650 C in 0.1 seconds, then held at 650 C for 5 seconds, then quenched to 400 C, held at 400 C for 60 seconds, and finally quenched to room temperature
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Using the time-temperature-transformation diagram, what steel phases would you generate by cooling from 900ºC A. quenching in cold water to 520ºC in 0.5 second, holding the sample temperature constant for 1000 seconds at 520ºC, and then quenching to room temperature B. cooling down to room temperature over a period of 2 weeks?