36AsiacellO Homework 4 -...->3 ClassMaterials Eng. Dep.Heat TreatmentIsmail Ibrahim MarhoonHomework 4Q1: 1.5 in diameter steel part is quenched in oil with no agitation. (H=0.20).If we use a 4340; 4140; 8640; 5140; 1040 steel, what would be the hardnessnumber at the center of the part?Q2: Determine the best quenching medium to produce a minimum hardnessof HRC 40 at the center of a 3.75 cm diameter 4320 steel bar.GivenCingrate t 00c00143to434050408640ab9310304320105010401020it 1 1 2n102030Jominy distance th of an inch)Die he eted eTABLE The N canticient, or seveity of the querch, far severalguenehing sedlaH CoefticientCoaling Rate at he Centerof a l-in. Bar (CA)MediumOl no taton)04 anitation)0251845HyD inc agtationH0 fegiutontBrine Ino agtaton)Brine lapttiori104.0190206090230AdDISTANCE FROM OUENCHED END IN)DIAMETER IN)

Q1: 1.5 in diameter steel part is quenched in oil with no agitation. (H=0.20). If we use a 4340: 4140: 8640; 5140; 1040 steel, what would be the hardness number at the center of the part? Q2: Determine the best quenching medium to produce a minimum hardness of HRC 40 at the center of a 3.75 cm diameter 4320 steel bar.

Q1: 1.5 in diameter steel part is quenched in oil with no agitation. (H=0.20). If we use a 4340: 4140: 8640; 5140; 1040 steel, what would be the hardness number at the center of the part? Q2: Determine the best quenching medium to produce a minimum hardness of HRC 40 at the center of a 3.75 cm diameter 4320 steel bar.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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