Q1 Assume that int x[5] = (5,4,3,2,1}; What are the values of x after calling Swap(x+1, х+4); Swap (x*2, х+3); if the swap function is defined as follows void swap(int *pa, int *pb) { int t; t=*pb; *pb=*pa; pa=&t; }
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- : Write a small matrix library The library should have the following functions: double sumOfRow(const double mat[][MAX_COL], const int row, const int maxRow); double sumOfCol(const double mat[][MAX_COL], const int column, const int maxRow); void fillWithRandomNum(double mat[][MAX_COL], const int maxRow); void printMatrix(const double mat[][MAX_COL], const int maxRow);Problem Statement: Consider an input string TAM of letters ‘A’, ‘M’, and ‘T’. This string, which is given by the user, ends with ‘#’. It should be stored in a table (or array), called TAMUK. The number of each of these letters is unknown. We have a function, called SWAP(TAM,i,j), which places the ith letter in the jth entry of string TAM and the jth letter in the ith entry of TAM. Note that SWAP(TAM,i,j) is defined for all integers i and j between 0 and length(TAM)–1, wherelength(TAM) is the number of letters of TAM. Using our algorithmic language, write an algorithm, called Sort_TAM, which sorts the letters in the array TAMUK in a way that all T’s appear first, followed by all A’s, and followed by all M’s. The algorithm Sort_TAM should have one parameter: The array TAMUK. Also, your solution is correct only if the following four constraints are satisfied: - Constraint 1: Each letter (‘A’, ‘M’, or ‘T’) is evaluated only once. - Constraint 2: The function SWAP(TAM,i,j) is used…Problem Statement: Consider an input string TAM of letters ‘A’, ‘M’, and ‘T’. This string, which is given by the user, ends with ‘#’. It should be stored in a table (or array), called TAMUK. The number of each of these letters is unknown. We have a function, called SWAP(TAM,i,j), which places the ith letter in the jth entry of string TAM and the jth letter in the ith entry of TAM. Note that SWAP(TAM,i,j) is defined for all integers i and j between 0 and length(TAM)–1, where length(TAM) is the number of letters of TAM. 1. Using our algorithmic language, write an algorithm, called Sort_TAM, which sorts the letters in the array TAMUK in a way that all T’s appear first, followed by all A’s, and followed by all M’s. The algorithm Sort_TAM should have one parameter: The array TAMUK. Also, your solution is correct only if the following four constraints are satisfied: - Constraint 1: Each letter (‘A’, ‘M’, or ‘T’) is evaluated only once. - Constraint 2: The function SWAP(TAM,i,j) is used only…
- Problem Statement: Consider an input string TAM of letters ‘A’, ‘M’, and ‘T’. This string, which is given by the user, ends with ‘#’. It should be stored in a table (or array), called TAMUK. The number of each of these letters is unknown. We have a function, called SWAP(TAM,i,j), which places the ith letter in the jth entry of string TAM and the jth letter in the ith entry of TAM. Note that SWAP(TAM,i,j) is defined for all integers i and j between 0 and length(TAM)–1, where length(TAM) is the number of letters of TAM. 1. Using our algorithmic language, write an algorithm, called Sort_TAM, which sorts the letters in the array TAMUK in a way that all T’s appear first, followed by all A’s, and followed by all M’s. The algorithm Sort_TAM should have one parameter: The array TAMUK. Also, your solution is correct only if the following four constraints are satisfied: - Constraint 1: Each letter (‘A’, ‘M’, or ‘T’) is evaluated only once. - Constraint 2: The function SWAP(TAM,i,j) is used only…Write the C equivalent “train” function #void train(int*A, int*B, int*C, int k) train: add $t4, $0, $0bus: add $t5, $t4, $a1 lw $t6, 0($t5) add $t5, $t4, $a2 lw $t7, 0($t5) add $t6, $t6, $t7 add $t5, $t4, $a0 sw $t6, 0($t5) addi $t4, $t4, 4 slt $t5, $t4, a3 bne $t5, $0, bus jr raSuppose you have two objects of Doubly Linked List D1 and D2. Each object is representing a different Doubly Linked List. Write a function to concatenate both doubly linked lists. The concatenation function must return the address of head node of concatenated Doubly Linked List, and it must take two Node* parameters. You need to keep in mind all exceptional cases for example what if either one of the doubly linked lists is empty? Perform this task on paper, take a clear picture of solution and paste it in answer section.
- Implement the function below. void swap(int pos1, int pos2){} Initial code to be completed: class ArrayList : public List { int* array; int index; int capacity; void dyn_all_add(){ int cap = ceil(capacity * 1.5); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } void dyn_all_rem(){ int cap = capacity - (capacity/3); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } public: // CONSTRUCTOR ArrayList() { capacity = 4; array = (int*)malloc(capacity); index = 0; } int add(int num) { if (index == capacity){ dyn_all_add(); } *(array + index) = num; index++; return index; } int get(int pos){ if (pos-1 < index){ return *(array + pos-1); } return -1; } int size(){ return index; }…2.2.14 Combining sorted queues. Create a static function that accepts two sorted queues as parameters and returns a queue formed by merging the queues into sorted order. 2.2.15 Mergesort from the bottom of the queue. Create a bottom-up mergesort implementation using the following method: Create N queues, each containing one of the things, given N items. Make a queue out of the N queues. Then, repeat Exercise 2.2.14's merging process on the first two queues, and finally, reinsert the combined queue.Repeat until there is just one queue in the queue of queues.In the Mergesort, the idea is to merge two arrays or list of two numbers, where each of those arrays are sorted. The merged array becomes fully sorted. The following code snippet makes the process of merge happen. Assume an array A={4, 11, 2, 9, 6}, where we want to split that array and then merge it. If we call the function "merge(A, 0, 2, 4)", how would the array A look like after the merge operation?* 4, 11, 2, 9, 6 2, 4, 6, 9, 11 4, 11, 9, 2, 6 4, 11, 6, 9, 2 11, 9, 6, 4, 2 4, 9, 6, 11, 2
- Implement the following function without using any additional data structure, and without sorting the input vectors. /* Given two vectors of integers, check if the two vectors contain same set of values: e.g., V1=[3,4,10,4,10,11] and V2=[3,3,4, 11, 10] stores same set int: {3, 4, 10, 11}. Note that duplicates are removed when considering set */ @param list1, list2: two vectors of integers@pre: list1, list2 have been initialized@post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameSet (const vector<int> & list1, const vector<int> & list2) {//for each value in list1, check if it appears in list2, if not, return false //for each value in list2, check if the value appears in list1, if not return false //return true}The set of all non-negative integers x less than 16 such that x2 is an even integer can be described as the set: (Note: The required set must include as elements all non-negative integers x such that all the requirements for the set are met.) a. {x| x ∈ Z≥, x < 16, x2 = 2k for some k ∈ Z} b. {x| x ∈ Z≥, x < 16, x2 = 2k for some k ∈ Z+} c. {0, 2, 4, 16, 36, 64, 100, 144, 196} d. {0, 2, 4}def find_root4(x, epsilon): ''' IN PYTHON Assume: x, epsilon are floating point numbers and epsilon > 0 Use bisection search to find the following root of x such that If x >=0, return y such that x - epsilon <= y ** 2 <= x + epsilon Else, return y such that x - epsilon <= y ** 7 <= x + epsilon Note: You must use bisection search to implement the function. ''' pass