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Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (25), so 5bits. TAG LINES WORD 4 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 1 1 1

Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (25), so 5bits. TAG LINES WORD 4 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 1 1 1

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (2°), so 5bits. ТAG LINES WORD 4 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 1 1 1 0011 0011 0100 ТAG LINES WORD 3 3 4
Transcribed Image Text:Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How is a 12-bit memory address divided into tag, line number, and byte number? Block size =8byte (2³), so 3bits. Cache of 32 lines (2°), so 5bits. ТAG LINES WORD 4 3 Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 TAG LINES WORD 1 1 1 0011 0011 0100 ТAG LINES WORD 3 3 4
Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine . How is a 12-bit memory address divided into tag, line number, and byte number? Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 0011 0011 0100 (1) How is a 12-bit memory address divided into tag, line number and byte number? TAG ( 12-5-3) = 8 LINE = 5 bits WORD - 3 bits (2) Into what line would a byte with following address be stored? 0001 0001 0001 1011 - Line 3 (00011)
Transcribed Image Text:Q1: Consider a machine with a byte addressable main memory of bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine . How is a 12-bit memory address divided into tag, line number, and byte number? Into what line would bytes with each of the following addresses be stored? 0001 0001 0001 0011 0011 0100 (1) How is a 12-bit memory address divided into tag, line number and byte number? TAG ( 12-5-3) = 8 LINE = 5 bits WORD - 3 bits (2) Into what line would a byte with following address be stored? 0001 0001 0001 1011 - Line 3 (00011)
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