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- Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'CDesign a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'CPerform floating point binary addition to the following: A: 1 10000011 10110111010000000000000 B: 0 10000000 10010011000100101000000 The result of A+B must be in be in 32-bit floating point. You can also check the answer in decimal.
- USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…b) There are five binary or hexadecimal numbers and six decimal conversions. Draw a line to connect each binary/hexadecimal to decimal number. Binary/Hexadecimal Decimal 4E 78 11011010 157 10011101 167 A7 25 19 218Q1) Do as required. a) Express decimal number (-123) in binary as an 8-bit sign-magnitude form. b) Add the BCD numbers: 10011000 + 10010111
- 1. An arithmetic system operates with 3-digit decimal numbers with sign presented in BCD (12 bits), negative numbers utilize the 10's complement form, one decimal digit (4 bits) is occupied by sign: 0 for "+" and 9 for "-". 1a) Show the most positive and the most negative numbers in both decimal and BCD forms. 1b) Present numbers A=+36 and B= -42 in BCD. 1c) Present the 10's complements of A and B in BCD. 1d) Perform the following operations bit-by-bit, show carries, apply BCD correction (add 6) when necessary (the sum of two decimal digits is greater than 9). 1d1) A+B in BCD. 1d2) A - B = A+(-B) in BCD by addition of A and the 10's complement of B. 1d3) B-A= B + (-A) in BCD by addition of B and the 10's complement of A.Q1 Count in Octal from 0 to 22. Q2 Convert (10010100011), to Hexadecimal. Q3 Express the decimal number (- 35) as an 8-bit number in 2's complement form.Consider two 8-bit inputs, A = $52 and B = $C3 to the arithmetic and logic unit (ALU). Compute R =A + B. Express R in the hexadecimal form $-- : -61 Express N-Z-V-C bits in the form ----:
- 21. Express the decimal number -37 as an 8-bit number in sign-magnitude. a. 10100101 b. 00100101 c. 11011000 d. 11010001bit numbers and store lower byte of the result in accumulator A and higher byte in accumulator B.. Similarly lower byte of 2nd number is stored in R2 and higher byte in R3. Now subtract these two 16 numbers in the RAM such that lower byte of 1t number is stored in R0 and higher byte in RI. manipulate 16 bits numbers as well. Write an assembly language program that stores two 16 bits 8051 is an 8-bit microcontroller that performs arithmetic on 8-bit numbers. However, we can Question#3: 8051 is an 8-bit microcontroller that performs arithmetic on 8-bit numbers. HoweveThe num ber -256can be represented usingwhich signed num ber representation method? a.7 bit 2s com plement b.9 bit unsigned birary c.8 bit one's com plement d.9 bit one's com plement e. None of the other choices.