Q1. A simple bar element is shown below. It is initially horizontal, with length L. Under some loading, the free end deforms by u in the x-direction and v in the y-direction. Show that the axial Green strain is: 1(u? + v EG L2 The displacement of the bar element free end is u=0.05, v=0.15 and the length is L=0.5, calculate the error in axial strain if the small strain formulation is used.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.9P: An clement of material subjected to plane strain (see figure) has strains of x=280106 , y=420106 ,...
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Q1. A simple bar element is shown below. It is initially horizontal, with length L. Under some loading,
the free end deforms by u in the x-direction and v in the y-direction.
Show that the axial Green strain is:
1(u? + v2
EG =
L2
(
The displacement of the bar element free end is u=0.05, v=0.15 and the length is L=0.5, calculate the
error in axial strain if the small strain formulation is used.
Transcribed Image Text:Q1. A simple bar element is shown below. It is initially horizontal, with length L. Under some loading, the free end deforms by u in the x-direction and v in the y-direction. Show that the axial Green strain is: 1(u? + v2 EG = L2 ( The displacement of the bar element free end is u=0.05, v=0.15 and the length is L=0.5, calculate the error in axial strain if the small strain formulation is used.
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