Q14. Rotational absorption of a diatomic molecule AB occurs with V.-200 cm³ and the spacing between neighboringlines is 20.89 cm¹. Given u = 1.327x10kg, find the AB bond distance in nm.D) 0.152E) 0.133A) 0.128B) 0.033C) 0.142F) 0.158

We know that in rotational spectra of di atomic molecule like AB lines are equally spaced by 2B. B =…

Q14. Rotational absorption of a diatomic molecule AB occurs with V₁-200 cm³ and the spacing between neighboring lines is 20.89 cm³¹. Given μ = 1.327x10 kg, find the AB bond distance in nm. D) 0.152 E) 0.133 A) 0.128 B) 0.033 C) 0.142 F) 0.158

Q14. Rotational absorption of a diatomic molecule AB occurs with V₁-200 cm³ and the spacing between neighboring lines is 20.89 cm³¹. Given μ = 1.327x10 kg, find the AB bond distance in nm. D) 0.152 E) 0.133 A) 0.128 B) 0.033 C) 0.142 F) 0.158

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter15: Introduction To Electronic Spectroscopy And Structure

Section: Chapter Questions

Problem 15.69E

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Question

Q14. Rotational absorption of a diatomic molecule AB occurs with V.-200 cm³ and the spacing between neighboring
lines is 20.89 cm¹. Given u = 1.327x10
kg, find the AB bond distance in nm.
D) 0.152
E) 0.133
A) 0.128
B) 0.033
C) 0.142
F) 0.158

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