Q2. How many grams of BaCl2 are formed in the neutralization of 393 mL of 0.171 M HCl(aq) with an aqueous solution of Ba(OH)2? (Mw(BaCh): 208.23 g/mol) Ba(OH)>(aq) + 2HCI(aq) → BaCh(aq) + 2H;O(1)
Q2. How many grams of BaCl2 are formed in the neutralization of 393 mL of 0.171 M HCl(aq) with an aqueous solution of Ba(OH)2? (Mw(BaCh): 208.23 g/mol) Ba(OH)>(aq) + 2HCI(aq) → BaCh(aq) + 2H;O(1)
Introductory Chemistry: A Foundation
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Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
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Problem 134AP
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![Q2. How many grams of BaCl2 are formed in the neutralization of 393 mL of 0.171 M HCI(aq) with an
aqueous solution of Ba(OH)2? (Mw(BaCl): 208.23 g/mol)
Ba(OH)»(aq) + 2HCI(aq)
BaC2(aq) + 2H2O(1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e44a62f-1d30-4b91-becd-622eed605bbf%2F9055bdd0-c0eb-4b6d-8b49-2e2707ecd5e6%2Fjxz5yk5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2. How many grams of BaCl2 are formed in the neutralization of 393 mL of 0.171 M HCI(aq) with an
aqueous solution of Ba(OH)2? (Mw(BaCl): 208.23 g/mol)
Ba(OH)»(aq) + 2HCI(aq)
BaC2(aq) + 2H2O(1)
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