Q2/A dog running in an open field has components of velocity Vx = 2.6 m/s and Vy = -1.8 m/s at t1 = 10.0 s. For the time interval from t1 = 10.0 s to t2 = %3D %3D 20.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 31o measured from the +x-axis toward the +y-axis. At t2 = 20.0 s, (a) what are the x- and y- components of the dog's velocity? (b) What are the magnitude and direction of the dog's velocity? (c) Sketch the velocity vectors at t1 and ?t2. How do these two vectors differ

Q2/A dog running in an open field has components of velocity Vx = 2.6 m/s and Vy = -1.8 m/s at t1 = 10.0 s. For the time interval from t1 = 10.0 s to t2 = %3D %3D 20.0 s, the average acceleration of the dog has magnitude 0.45 m/s2 and direction 31o measured from the +x-axis toward the +y-axis. At t2 = 20.0 s, (a) what are the x- and y- components of the dog's velocity? (b) What are the magnitude and direction of the dog's velocity? (c) Sketch the velocity vectors at t1 and ?t2. How do these two vectors differ

Name: Q2/A dog running in an open field hascomponents of velocity Vx = 2.6
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Description: Q2/A dog running in an open field hascomponents of velocity Vx = 2.6 m/sand Vy = -1.8 m/s at t1 = 10.0 s. For thetime interval from t1 = 10.0 s to t2 =%3D%3D20.0 s, the average acceleration ofthe dog has magnitude 0.45 m/s2and direction 31o measured

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 2P: A hiker walks 2.00 km north and then 3.00 km east, all in 2.50 hours. Calculate the magnitude and...

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