Q3/ A parallel plate capacitor whose plates are (15 cm X 4 cm) and separated by 1 mm air gap and connected to a 24 V battery (E,-8.85x1012 C’N.m². Calculate the followings; 1- The capacitance of the capacitor. 2- The charge on each plate. 3- The electric field across the capacitor.

Q3/ A parallel plate capacitor whose plates are (15 cm X 4 cm) and separated by 1 mm air gap and connected to a 24 V battery (E,-8.85x1012 C’N.m². Calculate the followings; 1- The capacitance of the capacitor. 2- The charge on each plate. 3- The electric field across the capacitor.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 35P: a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a...

See similar textbooks

Related questions

Q: Q5/ An electric field of 8.5 x 10 V/m is desired between two parallel plates each of (7 cm x 8 cm)…

A: The electric field, E=8.5×105 V/m The area, A=7×10-2 m×8×10-2 m=56×10-4 m2 The distance,…

Q: 6. The area of the capacitor plates of a capacitor is 1.7x10®m². The capacitor contains a teflon…

A: The answer is below

Q: A parallel plate capacitor has square plates of side 5 cm² and separated by a distance of 1 mm. (a)…

Q: 3) Below is a picture of a 12.000 Volt battery connected to a capacitor that originally has a…

Q: A 2.00-nF parallel-plate capacitor is charged to an ini- tial potential difference AV; lated. The…

A: Given : C = 2.00 nF = 2 x 10-9 F ∆Vi = 100 V k = 5.00

Q: 24- A circular parallel plate capacitor has a diameter of 2.0 cm and a distance of 1.0 mm between…

Q: 1. The plates of a parallel-plate capacitor, which is separated by 1.5mm of air, are connected to a…

A: As 1,2,3 are three different questions I'm proceeding to solve 1st question ( according to our…

Q: A parallel plate capacitor having area 35 cm? and plate spacing 1.5 mm is charged to a potential…

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

A: From Question: Capacitance: A component's or circuit's ability to collect and retain energy in the…

Q: A parallel plate capacitor with plate separation of 4.0 cm has a plate area of 0.08 m2. What is the…

Q: An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 1.00 mm. The…

Q: A parallel plate capacitor has square plates of side 5 cm and separated by a distance of 1 mm. (a)…

Q: 6. A parallel-plate capacitor with a plate separation of d has a capacitance C in the absence of…

Q: When a potential difference of 162 V is applied to the plates of a parallel-plate capacitor, the…

A: C= Q/V =sigmaA/V C is capacitance Q is charge V is the voltage applied Also C= eA/d (e is…

Q: A parallel plate capacitor has square plates of side 5 cm and separated by 1 mm. (a) Calculate the…

A: Given: Side = 5 cm or 0.05 m Separation d = 1 mm or 0.001 m V = 10 V Area A = (0.05)2 =…

Q: The area of the capacitor plates of a capacitor is 2.1x108m2. The capacitor contains a polyvinyl…

Q: A parallel-plate capacitor has plates of 4.50 cm by 4.00 cm. The plates are separated by a…

A: Given data: Sides of plate = 4.50 cm by 4.00 cm Distance between plates (d) = 0.300 mm Dielectric…

Q: Question A8 а) Give the definition of the electric potential at a point in an electric field. b)…

Q: QUESTION 1 What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic…

Q: arallel-plate capacitor has circular plates of diameter d, separated by distance x. There is no…

A: Please post the remaining questions separately!

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

A: Introduction: The capacitance is defined as the ratio of the charge on the plates and the potential…

Q: A parallel-plate capacitor is made by sandwiching 0.100-mm-thick sheets of paper (dielectric…

A: The capacitance of a parallel plate capacitor is given by: C = Kε0Ad where K is dielectric constant…

Q: 1. What is the value of the charge on each plate of a 0.06 µF capacitor when the potential…

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

A: Capacitance of a parallel plate capacitor is defined as the charge per unit potential difference…

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

A: Introduction: The capacitor is a two-terminal passive device that is used to store electrical energy…

Q: Why is it that we model the parallel plate capacitor using the electric field of of an infinite…

Q: Q3/ A parallel plate capacitor whose plates are (15 cm X 4 cem) and separated by 1 mm air gap and…

Q: If the magnitude of the electric field in air exceeds roughly 3 x 10° N/C, the air breaks down and a…

Q: A parallel-plate capacitor with plate area 5.8 cm? cm- and air-gap separation 0.25 mm is connected…

A: Given that, the value of voltage and area of plate and area of the plates and firstly it is fully…

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

Q: An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 3.00 mm. The…

A: a) The required capacitance is,

Q: 4. Figure 3 shows a capacitor that is constructed from two conductive metal plates 20 cm x 30 cm…

A: The capacitor is a device which can store charge. The given figure is a parallel plate capacitor, to…

Q: What is the capacitance of a parallel plate capacitor in vacuum? Sol. The basic definition for…

A: Capacitor is a device used to store electrical charge and electrical energy. Question :…

Q: Q2: A parallel plate capacitor of area A and separation d is connected to the battery to charge the…

A: Given that Area=A separation=d potential difference =V0 calculate the energy stored before and…

Q: Lightning As a crude model for lightning, consider the ground to be one plate of a parallel-plate…

A: The required capacitance is,

Q: A parallel plate capacitor is constructed with plates of areas 0.033 m² and separation 0.8 mm. (a)…

Q: Q5/ An electric field of 8.5 x 10° V/m is desired between two parallel plates each of (7 cm x 8 cm)…

Q: 1.A parallel plate capacitor has square plates of side 8 cm and separated by a distance of 2 mm. (a)…

A: As per our guideline, I have solved the first question, Please post other questions separately.

Concept explainers

Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

Q3/ A parallel plate capacitor whose plates are (15 cm X 4 cm) and
separated by 1 mm air gap and connected to a 24 V battery (ɛ,=8.85x1012
C²/N.m2.
Calculate the followings;
1- The capacitance of the capacitor.
2- The charge on each plate.
3- The electric field across the capacitor.
4- The energy stored in the capacitor.
5- If a slab of paper with dielectric constant K=3.25 is inserted between the
plates, Find the new value of charge on each plate.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 18.85×

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A parallel-plate capacitor with capacitance C0 stores charge of magnitude Q0 on plates of area A0 separated by distance d0. The potential difference across the plates is V0. If the capacitor is attached to a battery and the charge is doubled to 2Q0, what are the ratios (a) Cnew/C0 and (b) Vnew/V0? A second capacitor is identical to the first capacitor except the plate area is doubled to 2A0. If given a charge of Q0, what are the ratios (c) Cnew/C0 and (d) Vnew/V0? A third capacitor is identical to the first capacitor, except the distance between the plates is doubled to 2d0. If the third capacitor is then given a charge of Q0, what are the ratios (e) Cnew/C0 and (f) Vnew/V0?
(a) What is the capacitance of a parallel plate capacitor having plates of area 1.50 m2 that are separated by 0.0200 mm of neoprene rubber? (b) What charge does it hold when 9.00 V is applied to it?
True or False? (a) From the definition of capacitance C = Q/V it follows that an uncharged capacitor has a capacitance of zero. (b) As described by the definition of capacitance, the potential difference across an uncharged capacitor is zero.
(a) What is the capacitance of a parallel-plate capacitor with plates of area 1.50 m that are separated by 0.0200 mm of neoprene rubber? (b) What charge does it hold when 9.00 V is applied to it?
A parallel-plate capacitor with capacitance C0 stores charge of magnitude Q0 on plates of area A0 separated by distance d0. The potential difference across the plates is V0. If the capacitor is attached to a battery and the charge is doubled to 2Q0, what are the ratios (a) Cnew/C0 and (b) Vnew/V0? A second capacitor is identical to the first capacitor except the plate area is doubled to 2A0. If given a charge of Q0, what are the ratios (c) Cnew/C0 and (d) Vnew/V0? A third capacitor is identical to the first capacitor, except the distance between the plates is doubled to 2d0. If the third capacitor is then given a charge of Q0, what are the ratios (e) Cnew/C0 and (f) Vnew/V0?
(a) When a 9.00-V battery is connected to the plates of a capacitor, it stores a charge of 27.0 C. What is the value of the capacitance? (b) If the same capacitor is connected to a 12.0-V battery, what charge is stored?
A parallel-plate capacitor has plates of area A = 7.00 102 m2 separated by distance d = 2.00 104 m. (a) Calculate the capacitance if the space between the plates is filled with air. What is the capacitance if the space is filled half with air and half with a dielectric of constant = 3.70 as in (b) Figure P16.56a, and (c) Figure P16.56b? (Hint: In (b) and (c), one of the capacitors is a parallel combination and the other is a series combination.) Figure P16.56
A capacitor is constructed from two square, metallic plates of sides and separation d. Charges +Q and Q are placed on the plates, and the power supply is then removed. A material of dielectric constant is inserted a distance x into the capacitor as shown in Figure P25.49 (page 690). Assume d is much smaller than x. (a) Find the equivalent capacitance of the device. (b) Calculate the energy stored in the capacitor. (c) Find the direction and magnitude of the force exerted by the plates on the dielectric. (d) Obtain a numerical value for the force when x = /2, assuming = 5.00 cm, d = 2.0 mm, the dielectric is glass ( = 4.50), and the capacitor was charged to 2.00 103 V before the dielectric was inserted. Suggestion: The system can be considered as two capacitors connected in parallel. Figure P25.49
(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 5.00 cm2? (b) Find the maximum charge if polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00 106 V/m and that of polystyrene is 24.0 106 V/m.
A parallel-plate capacitor with plates of area LW and plate separation t has the region between its plates filled with wedges of two dielectric materials as shown in Figure P25.48. Assume t is much less than both L and W. (a) Determine its capacitance. (b) Should the capacitance be the same if the labels 1 and 2 are interchanged? Demonstrate that your expression does or does not have this property. (c) Show that if 1 and 2 approach equality to a common value , your result becomes the same as the capacitance of a capacitor containing a single dielectric: C = 0LW/t. Figure P25.48
a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a 6.00-V battery. (a) What is the capacitance? (b) How much charge is stored on the plates? (c) What is the electric field between the plates? (d) Find the magnitude of the charge density on each plate. (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers?
Unreasonable Results (a) A certain parallel plate capacitor has plates of area 4.00 m2 separated by 0.0100 mm of nylon, and stores 0.170 C of charge. What is the applied voltage? (b) What is unreasonable about this result? (c) Which assumptions are responsible or inconsistent?