Q3/ Answer True or False for each of the following: 1) Salicylic acid can be prepared from Kolb-Schmitt reaction 2) Boat is the more stable conformation of cyclopentane 3) Benzoin can be prepared from reaction benzaldehyde with acetone 4) The enone can be prepared from Mannich reaction 5) The benzilic acid rearrangement containing 1,2-methyl shift CH3 H₂C 6) The structure of borneol is HO 7) The IUPAC name of this compound 8) Phenol + CHC13 NaOH CH3 H₂C CH3 salicylaldehyde CH3 is 1,7,7-trimethyl bicyclo [2.2.1] heptene

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter10: Alcohols
Section: Chapter Questions
Problem 10.33P: Two diastereomeric sets of enantiomers, A/B and C/D, exist for 3-bromo-2-butanol. When enantiomer A...
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Q3/ Answer True or False for each of the following:
1) Salicylic acid can be prepared from Kolb-Schmitt reaction
2) Boat is the more stable conformation of cyclopentane
3) Benzoin can be prepared from reaction benzaldehyde with acetone
4) The enone can be prepared from Mannich reaction
5) The benzilic acid rearrangement containing 1,2-methyl shift
H₂C-
CH3
6) The structure of borneol is
HO
7) The IUPAC name of this compound
8) Phenol + CHC13
NaOH
CH3
H3C-
CH3
salicylaldehyde
CH3
is 1,7,7-trimethyl bicyclo [2.2.1] heptene
Transcribed Image Text:Q3/ Answer True or False for each of the following: 1) Salicylic acid can be prepared from Kolb-Schmitt reaction 2) Boat is the more stable conformation of cyclopentane 3) Benzoin can be prepared from reaction benzaldehyde with acetone 4) The enone can be prepared from Mannich reaction 5) The benzilic acid rearrangement containing 1,2-methyl shift H₂C- CH3 6) The structure of borneol is HO 7) The IUPAC name of this compound 8) Phenol + CHC13 NaOH CH3 H3C- CH3 salicylaldehyde CH3 is 1,7,7-trimethyl bicyclo [2.2.1] heptene
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