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- After the execution of the following program, the content of PORTB is: PORTB EQU 0F81H MOVLW 0FFH MOVWF PORTB BSF PORTB, 7 Select one: a. 0FFH b. 11111110 binary c. 01111111 binary d. 11111101 binary0.What is the output of the given code? if 79>78puts "True".upcaseif 9>8puts "True".reverseif 7==7puts "equal".downcaseendendendI am still getting the wrong output with the updated code with the fix. This is the updated coded that you provided: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states li $v0, 1 move $a0, $t0 syscall li $v0, 1 move $a0, $t1 syscall li $v0, 1 move $a0, $t2 syscall li $v0, 1 move $a0, $t3 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with…
- This is the updated code that I have: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states move $a0, $t0 li $v0, 1 syscall move $a0, $t1 li $v0, 1 syscall move $a0, $t2 li $v0, 1 syscall move $a0, $t3 li $v0, 1 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with 0x7fff and lower mask with 0x8000 lui $t0, 0x7fff ori $t0, $t0,…A. The original Caesar cypher shifts each character by one: a becomes b, z becomes a, and so on. Let's make it a bit harder, and allow the shifted value to come from the range 1..25 inclusive. Moreover, let the code preserve the letters' case (lower-case letters will remain lower-case) and all non-alphabetical characters should remain untouched. Your task is to write a program which: asks the user for one line of text to encrypt; asks the user for a shift value (an integer number from the range 1..25 - note: you should force the user to enter a valid shift value (don't give up and don't let bad data fool you!) Test your code using the data we've provided. Test data Sample input: abcxyzABCxyz 123 2 Sample output: cdezabCDEzab 123 Sample input: The die is cast 25 Sample output: Sgd chd hr bzrsCreate an RLE class that uses fixed-length encoding to reduce ASCII bytestreams with a limited number of characters, including the code as part of the compressed bitstream. Add code to compress() to generate a string alpha containing all of the unique letters in the message and use it to generate an Alphabet for use in compress(), prepend alpha (8-bit encoding plus its length) to the compressed bitstream, and then add code to expand() to read the alphabet before expansion.
- i have this code .ORIG x3000SetupLEA R0, InfoPUTS ADD R6, R6, #5; Init Main Loop counter (loop 5 times) ;Print first 2 Fib values before starting;----- Your Code Here -----;LD R1, #0 JSR printNum LD R2, #1 JSR printNumJSR printNum ; Print the value in R2 JSR printCommaSpace ; Print comma and space ;----- End Your Code Here -----;;Loop and call subroutines to calculate each subsequent value in the sequence;Exit the loop once all single-digit values in the sequence have been printedMainLoop ;----- Your Code Here -----; JSR calcNextFib JSR printNum JSR printCommaSpaceADD R6, R6, #-1BRz Done BR MainLoop ;----- End Your Code Here -----; Done HALT ;-----------------------------------;Subroutines;----------------------------------- ;Uses R1 and R2 to calc next value in Fibonacci sequence;When complete, Fib2 (R2) will contain the new Fib number;and Fib1 (R1) will contain the previous value of Fib2 (R2)calcNextFib;----- Your Code Here -----;ST R1, SaveR3 ; Save R1ST R2,…MIPS Code below:- new_ln: .asciiz "\n" .textmain: li $v0,4la $a0,promptsyscall #output prompt for userli $v0,5syscall #input the integer and save it to $s0move $s0,$v0li $t0,2 #check if the input is odd or even bydiv $t0,$s0,$t0 #division by 2; save rem in St1mfhi $t1if: bnez $t1,else # if remainder is 0li $v0,4 #print number is evenla $a0,label2syscallj endifelse: li $v0,4 #else print number is oddla $a0,label1syscallli $v0,4 # print newlinela $a0,new_lnsyscallendif: li $v0,10 #exit programsyscall Note:- Please read this above MIPS code and now make some changes in this same above code and modify as the given instruction in the picture.COUNT EQU 0x37 MOVLW d'30' MOVWF COUNT MOVLW 0AGAIN ADDLW 4 DECFSZ COUNT, F GOTO AGAIN MOVWF PORTB Questions: Find the value at PORTB. Find how many loops there are in total.
- /main.cpp:15:24 Implicit conversion loses integer precision: 'unsigned long' to 'int' #include<stdio.h>#include<string.h>int main(){ char thVl[20],thTmp; int q,thLngth; printf("Input: "); scanf("%s",thVl); thLngth=strlen(thVl)-1; for(q=0;q<strlen(thVl)/2;q++) { thTmp=thVl[q]; thVl[q]=thVl[thLngth]; thVl[thLngth--]=thTmp; } printf("\nReversed thVl: %s",thVl);}suppose r0 = 0x20000000 and r1 = 0x01234567. what is the content of r0 and r1 after the following line of code is executed: LDRH r1, [r0], #4Question What is the value of R5 and R6 after executing the code snippet shown below?Assume that the address of myStr is OX0FF00myStr: string "ABCD"mov #myStr, R5mov @R5,R6value of R5: ?Value of R6: ?Note: 1. ASCII value of "A is Ox41 And 'a' is 0x612. Write the numbers in hexadecimal starting with 0X3. Write the command in coital fetters