Q5. When we design a 100-kW, 10000-rpm synchronous generator, should we use laminated silicon steel as the material of stator iron core? Give your explanation. Q6. When we design a 10-W, 2-rpm synchronous motor, should we use laminated silicon steel as the material of rotor iron core? Give your explanation.
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- The open-circuit characteristic of a shunt generator when driven at normal speed is as;Field current (A)0.51.01.52.02.53.03.5O.C. volts (V)54107152185210230240The resistance of armature circuit is 0.1 Ω. Due to armature reaction the effective field current is given by the relation Ish (eff.) = Ish − 0.003 Ia. Find the shunt field circuit resistance that will give a terminal voltage of 220 V with normal speed (a) on open circuit (b) at a load current of 100 A. Also find (c) number of series turns for level compounding at 220 V with 100 A armature current; take number of shunts turns per pole as 1200 and (d) No. of series turns for over-compounding giving a terminal voltage of 220 V at no-load and 230 V with 100 A armature current.The open-circuit characteristic of a shunt generator when driven at normal speed is as;Field current (A)0.51.01.52.02.53.03.5O.C. volts (V)54107152185210230240The resistance of armature circuit is 0.1 Ω. Due to armature reaction the effective field current is given by the relation Ish (eff.) = Ish − 0.003 Ia. Find the shunt field circuit resistance that will give a terminal voltage of 220 V with normal speed (a) on open circuit (b) at a load current of 100 A. Also find (c) number of series turns for level compounding at 220 V with 100 A armature current; take number of shunts turns per pole as 1200 and (d) No. of series turns for over-compounding giving a terminal voltage of 220 V at no-load and 230 V with 100 A armature current.please answer only part C and DA 3 phase 4MVA, 12 kV star connected synchronous generator has Zs= 0.8+J30 ohm. Using circle diagram only, find: 1. The output power developed at unity power factor with excitation equal to 1.25 of rated voltage. 2. The load angle and power factor if the generator supplies (1500 KW) at rated voltage and excitation lequal to (1.2) of rated voltage. 3. Repeat part (2) when .armature resistance is neglected
- A 20KW, 440V, short shunt compound dc generator has full load efficiency of 87%. If the resistance of the armature and interpoles is 0.4ohm and that of the series and shunt fields 0.25ohm and 240ohms respectively, calculate the combined bearing friction, windage and core loss of the machine A 10 kW 250 volts self-excited generator, when delivering rated load, has an armature-circuit voltage drop of 5% of the terminal voltage and a shunt field current equal to 5% of the rated load current. The resistance of the armature is 0.02 ohm. Calculate the voltage generated and power output.With the aid of mathematical expressions explain the following terms with respect to squirrel cage induction motorsi. Stray Lossesii. Air gap Poweriii. Rotational lossesiv. Friction and Windage lossesv. Stator Copper lossesvi. Rotor Copper lossesvii. Mechanical LossesWith the aid of mathematical expressions where necessary, explain the following terms with respect to squirrel cage induction motorsi. Stray Lossesii. Air gap Poweriii. Rotational lossesiv. Friction and Windage lossesv. Stator Copper lossesvi. Rotor Copper lossesvii. Mechanical Losses
- b. With the aid of mathematical expressions where necessary, explain the following terms with respect to squirrel cage induction motorsi. Stray Lossesii. Air gap Poweriii. Rotational lossesiv. Friction and Windage lossesv. Stator Copper lossesvi. Rotor Copper lossesvii. Mechanical LossesWith the aid of mathematical expressions where necessary, explain the following terms with respect to squirrel cage induction motorsi. Friction and Windage lossesii. Stator Copper lossesiii. Rotor Copper lossesiv. Mechanical LossesThe open-circuit characteristic of a shunt generator when driven at normal speed is as follows :Field current : 0.5 1.0 1.5 2.0 2.5 3.0 3.5 AO.C. volts : 54 107 152 185 210 230 240 VThe resistance of armature circuit is 0.1 Ω. Due to armature reaction the effective field current is givenby the relation Ish (eff.) = Ish − 0.003 Ia. Find the shunt field circuit resistance that will give a terminal voltageof 220 V with normal speed (a) on open circuit (b) at a load current of 100 A. Also find (c) number of seriesturns for level compounding at 220 V with 100 A armature current ; take number of shunt turns per pole as1200 and (d) No. of series turns for over-compounding giving a terminal voltage of 220 V at no-load and230 V with 100 A armature current.
- Two similar 6,600-V, 3-φ, generators are running in parallel on constant-voltage and frequency bus bars. Each has an equivalent resistance and reactance of 0.05 Ω and 0.5 Ω respectively and supplies one half of a total load of 10,000 kW at a lagging p.f. of 0.8, the two machines being similarly excited. If the excitation of one machine be adjusted until the armature current is 438 A and the steam supply to the turbine remains unchanged, find the armature current, the e.m.f. and the p.f. of the other alternator. [789 A, 7200 V, 0.556]A 150-kW 250-volt compound generator is connected long shunt. If the shunt field resistance is 20 ohms, what is the series field-current at full load? (Ans.: 612.5 A) write diagram, given, etc21 A 25 kW, 240 V self excited dc shunt generator has a field circuit resistance of 62.5 Ω, and an armature resistance of 0.05 Ω. When delivering rated current at rated speed and voltage, calculate % Efficiency when rotational losses are 1200W, and iron losses are 600W. Note that Copper losses must be calculated too. No Units! Please answer in typing format please ASAP for