The open-circuit characteristic of a shunt generator when driven at normal speed is as; Field current (A) 0.5 1.0 1.5 2.0 2.5 3.0 3.5 O.C. volts (V) 54 107 152 185 210 230 240 The resistance of armature circuit is 0.1 Ω. Due to armature reaction the effective field current is given by the relation Ish (eff.) = Ish − 0.003 Ia. Find the shunt field circuit resistance that will give a terminal voltage of 220 V with normal speed (a) on open circuit (b) at a load current of 100 A. Also find (c) number of series turns for level compounding at 220 V with 100 A armature current; take number of shunts turns per pole as 1200 and (d) No. of series turns for over-compounding giving a terminal voltage of 220 V at no-load and 230 V with 100 A armature current. please answer only part C and D
The open-circuit characteristic of a shunt generator when driven at normal speed is as;
Field current (A)
0.5
1.0
1.5
2.0
2.5
3.0
3.5
O.C. volts (V)
54
107
152
185
210
230
240
The resistance of armature circuit is 0.1 Ω. Due to armature reaction the effective field current is given by the relation Ish (eff.) = Ish − 0.003 Ia. Find the shunt field circuit resistance that will give a terminal voltage of 220 V with normal speed (a) on open circuit (b) at a load current of 100 A. Also find (c) number of series turns for level compounding at 220 V with 100 A armature current; take number of shunts turns per pole as 1200 and (d) No. of series turns for over-compounding giving a terminal voltage of 220 V at no-load and 230 V with 100 A armature current.
please answer only part C and D
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