Q6 If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25. a) State the point estimate .b) Determine the standard error and margin of error for a 90% confidence interval .c) Estimate the 90% confidence interval for the proportion of shopping mall customers who spend over $25. Interpret.

Q: The confidence interval was (52, 62) What was the point estimate? What was the margin of error?…

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Q: Use the confidence interval to find the margin of error and the sample mean. (1.52,2.06)

A: Given: Confidence interval is (1.52, 2.06) To determine: The margin error and The sample mean.…

Q: For the same sample statistics, which level of confidence would produce the widest confidence…

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Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

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Q: In a survey, people were asked whether they thought sun went around the planet Earth or vice versa.…

A: (a)   Obtain the proportion of people in the survey who believed the sun went around earth. The…

Q: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level E=

A: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level

Q: Find the margin of error for the given confidence level.

A: Margin of error :  In a confidence interval, the range of values above and below the sample…

Q: If n = 200 and p^ = 0.64, find the margin of error at a 95% confidence level.

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Q: A researcher would like to know the proportion of the households that has a cable subscription. She…

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Q: If n=160 and ˆp (p-hat) =0.48, find the margin of error at a 99% confidence level

A: Given Data: p^=0.48n=160   We know that, p^-pp^(1-p^)n~ Normal(0,1)

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: If n=11, ¯xx¯(x-bar)=32, and s=9, find the margin of error at a 98% confidence level

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Q: Complete the statement by filling in the blank. When constructing a confidence interval for a…

A: We want to tell you which one is the correct choice.

Q: The confidence interval was (22, 26) What was the point estimate? What was the margin of error?

A: Given confidence interval was (22, 26)

Q: If n=23, ¯x (x-bar)=38, and s=5, find the margin of error at a 99% confidence level

A: The degrees of freedom is obtained as follows:

Q: 11. A television station surveys 200 customers and finds that 23% of customers watch the evening…

A: Margin of error = z*√(pq/n) Where z= z value            n=no of customer            q=1-p…

Q: How large is the sample if the confidence level is 97%, Ɛ = 2.5%  and ρ = .35?

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Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You…

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Q: If n=27, (x-bar)=46, and s=2, find the margin of error at a 98% confidence level Give your answer to…

A: Given : n = 27 x¯ = 46 s = 2 Confidence level = 98% = 0.98

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: The confidence interval was (77, 83) What was the point estimate? What was the margin of error?

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Q: 4. To estimate the mean retail price of designer jeans, a buyer sampled 19 retailers in New York…

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Q: A television sports commentator wants to estimate the proportion of Americans who "follow…

A: The value of confidence level (CL) is 0.95.

Q: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

A: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)

A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?

Q: Use the given confidence interval to find the margin of error and the sample mean. (71.7, 87.3)

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Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: 4) Out of the 440 people surveyed, a 110 said they listen to Spotify at least one a month. With the…

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Q: (a) Find a point estimate for the true proportion of all workers that would have hearing impairment.…

A: 8. A study was conducted on hearing impairment among workers in a construction site.

Q: What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c.…

A: Confidence Level = 90 Significance Level = α = (100-90)% = 0.1 Critical value = z* = 1.65   […

Q: What is the margin of error of a 95% confidence interval for the proportion that beat profit…

A: Given that sample size n = 162 Number of beat estimates, X = 104 At 95% confidence level, the…

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: If about 75% of the students of a certain university are expected to use a laptop for online…

A: Given,sample proportion (p^)=0.75margin of error(E)=0.05α=1-0.99=0.01α2=0.005Z0.005=2.5758…

Q: If n=19, a(x-bar)=31, and s=9, find the margin of error at a 80% confidence level Give your answer…

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Q: If n=12, ¯xx¯(x-bar)=48, and s=6, find the margin of error at a 98% confidence level

A: From the provided information, Sample size (n) = 12 Sample mean (x̄) = 48 Standard deviation (s) = 6…

Q: 3. Aresearcher wants to estimate the daily expenses of college students. He wants a 99% confidence…

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Q: Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a…

A: Solution: From the given information, the sample proportion is 18% and a margin of error is 4…

Q: A university planner wants to determine the proportion of undergraduate students who plan to attend…

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Q: The confidence interval was (64, 76) What was the point estimate? What was the margin of error?

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Q: (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or…

A: The confidence levels are 98% and 80%.

Q: Michelle, a student studying music, randomly sampled fellow music majors and asked whether they…

A: Given information- Confidence interval = (0.09, 0.26) We have to find margin of error. We know that-…

Q: Find the value oft within a) 90% confidence level and n = 10 b) 95% confidence level and n = 6 c)…

A: As per our guidelines we are supposed to answer only 3 sub-parts of any question so I am solving…

Q: If n=23, x(x-bar)=47, and s=3, find the margin of error at a 98% confidence level Give your answer…

A: Margin error is the difference between the estimated value and the original value. Here the critical…

Q: If n=10, ¯xx¯(x-bar)=44, and s=8, find the margin of error at a 80% confidence level

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Q: If n=12, x¯(x-bar)=47, and s=3, find the margin of error at a 80% confidence level

A: Margin of error (E): The margin of error for sample mean is given by,

Q: If n=23, ¤(x-bar)=34, and s=2, find the margin of error at a 98% confidence level Give your answer…

A: Given that, n = 23 Sample mean = 34 Standard deviation = 2 98% confidence level

Q: A TV report conducted a survey of 908 people in Phoenix metro area and found that 28% of the…

A: Given Total people n = 908 Probability p = 0.28 we are 94% confident that the true proportion of…

Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.

Q: Out of 300 people sampled, 78 had kids. Based on this, construct a 99% confidence interval for the…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.