Q7. calculate the half-life (t1/2) when the NO2 undergoes thermal decomposition, where the [NO2] = 2.5 x 10-2 mol L-1 at 600 K SUMMARY OUTPUT TIME + 1/[NO2] MOL L-1Regression StatisticsMultiple RR SquareAdjusted R SquareStandard ErrorObservationsANOVARegressionResidualTotalInterceptX Variable 1Multiple RR SquareAdjusted R SquareStandard ErrorObservationsANOVARegressionResidualTotalRegression StatisticsInterceptX Variable 10.9990753570.9981515690.9977818834.640839396Multiple RR SquareAdjusted R SquaStandard ErrorObservationsdfANOVASUMMARY OUTPUT TIME + [NO2] MOL L-1RegressionResidualTotalInterceptX Variable 1Regression Statistics7df1алнCoefficients Standard Error104.38977870.759535261560.9161433170.8393185780.8071822930.001121943df7SUMMARY OUTPUT TIME+ IN[NO2] MOL L-1SS58150.89635107.686951558258.5833156CoefficientsStandard Error0.008223571 0.000764476-1.80595E-05 3.53379E-060.9775959630.9556938670.9468326410.10672171773.162199020.01461727156Coefficients-4.773149167-0.003490881TIME (seconds) [NO2] mol L -100.010.0063601200.005181800.004182400.0035SS3.28756E-056.29379E-063.91693E-05SSMSF ignificance F58150.89635 2699.997 4.99E-0821.5373903F ignificance FMS3.28756E-05 26.11747 0.0037371.25876E-06Standard Error1/[NO2] MOL L-10.0727185920.000336142400.001/[NO2] mol L-1100.00158.73193.05239.23285.71350.00300.00In[NO2] mol L-1-4.61-5.07-5.26-5.48-5.65250.00200.00150.00100.00t StatP-value Lower 95% Upper 95% ower 95.0%Jpper 95.0%33.01176745 4.79E-07 96.26109 112.5185 96.26109 112.518551.96149855 4.99E-08 0.72196 0.79711 0.72196 0.7971150.000.00[NO2] MOL L-10.0120.010.0080.0060.004MSignificance F1.228373867 1.228373867 107.8512 0.0001430.056947624 0.0113895251.2853214910.00200050t StatP-value Lower 95% Upper 95% ower 95.0%Jpper 95.0%10.75714034 0.00012 0.006258 0.010189 0.006258 0.010189-5.11052582 0.003737 -2.7E-05 -9E-06 -2.7E-05 -9E-06IN[NO2] MOL L-1500.00-1.00-2.00-3.001/[NO2] mol L-1100-4.00-5.00-6.00-7.000100●150150200TIME[NO2] mol L -150200TIME250100t StatP-value Lower 95% Upper 95% ower 95.0%Jpper 95.0%-65.63863525 1.55E-08 -4.96008 -4.58622 -4.96008 -4.58622-10.38514299 0.000143 -0.00435 -0.00263 -0.00435 -0.00263250300150300350In [NO2] mol L-1350200TIME400400250O300350400

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Answered: Q7. calculate the half-life (t1/2)…

Q7. calculate the half-life (t1/2) when the NO2 undergoes thermal decomposition, where the [NO2] = 2.5 x 10-2 mol L-1 at 600 K

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter32: Radiochemical Methods

Section: Chapter Questions

Problem 32.12QAP

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