Ql :- The percentage composition of an organic sample are :- C- 24.6% , H = 2% and the rest is ( Cl ), calculate the E.F and the M.F, if the molecular weight of the compound =97 and the A.Wt of : C=12 , H=1 ,Cl = 35.5.
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- Consider a blend of mass 5g formed from 2.2 g of C12H24 and 2.8g of C998H1000 paraffin's:, What are Mn and Mw of the blend?0.004 C8H7NO3, 15mL ethanol, 0.002mol NaBH4 was used. HCl was used to acidify. It was then extracted with ether. Then it was dried and a mass of 0.32g was obtained. What is the balanced equation of this synthesis, and what is the limiting reagent?mass of cuso4: 7.00g. mass of fe: 2.00g. mass of filter paper: 1.50g. mass of cu solid: 2.16g. mass of dried filter paper and cu solid: 3.96g. limiting reagent: cuso4. calculate the moles of cu(s) formed along with the moles of limiting reagent used and ratio of moles of cu(s) formed/moles of limiting reagent.
- For the reaction C4H10 + O2 --> CO2 + H2O a) what weight of C4H10 in grams is needed for 3.01 x 10E23 particles of O2? b) how many moles of CO2 will be produced from 5.0 moles of C4H10? c) what weight in grams of H2O will be produced from 12.5 ml of C4H10? density (p)?of C4H10 = 0.506 g/mLC6H5Cl + 2 NH3 --> C6H5NH2 + NH4Cl Assume that 20.0 g of chlorobenzene at90% purity is mixed with 8.30 g of ammonia. a)What is the limiting reactant?Sulfur can be recovered from the hydrogen sulfide removed from crude oil deposits, a process known as sweetening, by roasting in air and using the sulfur dioxide initially formed to push the reaction to the final product: H2S(g) + O2(g) --> H2O(g) + SO2(g) H2S(g) + SO2(g) --> H2O(g) + S(s) The maximum number of kilograms of sulfur that can be isolated per kilogram of hydrogen sulfide entering the process is __________.
- The hydrated salt, MY3·xH2O, was heated strongly in a crucible to remove all the watermolecules of crystallization.The data are for this experiment are given in the table below.Mass of empty crucible and cover 29.73 gMass of crucible, cover, and hydrated salt 32.72 gMass of crucible, cover, and anhydrous salt 31.52 gMolar mass of anhydrous salt 241.88 g/mol(i) Calculate the % composition by mass of water in the hydrated salt.(ii) Determine the value of x.(iii) M is in Period 4 of the Periodic Table of the Elements.If Y = NO3–, identify the element M.(iv) What is the name of this hydrated salt? ___Balance the following equations. (Use the lowest coefficients.) (a) C3H8 + O2 CO2 + H2O(b) Fe2O3 + C Fe + CO(c) C4H8 + O2 CO2 + H2OAdipic acid, H2C6H8O4, is used to produce nylon. It is made commercially by a controlled reaction between cyclohexane ( C6H12 ) and O2:. (Only the 4th sub part (d) is needed to be answered). 2 C6H12 (l) + 5 O2 (g) → 2 H2C6H8O4 (l) + 2 H2O (g) (Given: Atomic Wts (g/mol): C= 12.01 ; H=1.01 ; O=16.00 ) If 25.0 g of cyclohexane is reacted with 20.0 g of O2, a. Identify the limiting reactant and excess reactant? b. How much in grams of the excess reactant will be left after the reaction? c. What is the theoretical yield in terms of the product adipic acid? d. If the actual yield is 33.5 g, what is the % yield of adipic acid?
- Given Active Ingredient: precipitated sulfur (ointment) Raw Materials: 500 g calcium polysulphide and 1.5 kg hydrochloric acid Actual Yield: 343.4g precipitated sulfur Formulation: 250 mg per jar Dosage form: Ointment packaging:100 jars per box Synthesis and Packaging (Need answer)- Balanced Chemical Equation:- % composition by mass of each compound:- Mass to Mass Stoichiometry Calculation:- Limiting Reagent:- Excess Reagent:- Amount (g) in excess: % Yield:- Number of dosage form and packaging that can be produced from stoichiometric solution:what is the coefficient in front of the O2 when the equation is balanced (using only whole numbers abs the lowest whole number ratio) C2H6O(g)+O2(g)>CO2(g)+H2O(g)A mixture weighing 28.516g containers 4.518g NH4CL, 15.20g SiO2, with the remainder NaCl. find the percent, weight, of each component. Show you method for making the calculations.