Quarterback, Cody, throws the football in a perfect parabolic arc to a receiver 40 yards downfield. The equation for the arc of his throw is y=-1/40(x-20)2(this “2”is a squared sign) +16 where c is horizontal distance and y is height above the ground. The defender has a vertical stretch of 9 feet. What would the horizontal distance be for the defender to catch the ball?. Describe how to determine the maximum distance the defensive player can be in front of the receiver to prevent the catch. Input the proper y-value, solve the equation for x and explain how to find the maximum distance PLEASEEEE the pic down below is the same problem

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Q: Cartesian

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Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.