QUESTION 1 The actual freezing point of dodecanol is 23.9°C, and its freezing point constant is 2.9°C/m. If 1.20 g of an unknown solid (non-electrolyte) are dissolved in 15.2 g of dodecanol producing a solution that freezes at 20.2°C, what is the molar mass of the unknown solid?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
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QUESTION 1
The actual freezing point of dodecanol is 23.9°C, and its freezing point constant is 2.9°C/m. If 1.20 g of an unknown solid (non-electrolyte) are dissolved in
15.2 g
of dodecanol producing a solution that freezes at 20.2°C, what is the molar mass of the unknown solid?
QUESTION 2
Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained an insoluble impurity?
lower because the change in temperature observed will be higher
higher because the change in temperature observed will be lower
same because there is no effect
higher because the change in temperature observed will be higher
O lower because the change in temperature observed will be lower
Transcribed Image Text:QUESTION 1 The actual freezing point of dodecanol is 23.9°C, and its freezing point constant is 2.9°C/m. If 1.20 g of an unknown solid (non-electrolyte) are dissolved in 15.2 g of dodecanol producing a solution that freezes at 20.2°C, what is the molar mass of the unknown solid? QUESTION 2 Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained an insoluble impurity? lower because the change in temperature observed will be higher higher because the change in temperature observed will be lower same because there is no effect higher because the change in temperature observed will be higher O lower because the change in temperature observed will be lower
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