QUESTION 1: The elevator system given in the figure moves up and down with a velocity of v=i m/sec. As the elevator starts to move, it reaches to its steady state angular velocity in 1 seconds. It is known that all the friction effects within the system are neglected. The other information related with the system are given as below: : Jm=1.25 kgm? Mass moment of inertia about the elevator shaft K-K : Jx=1 kgm² M-400 kg m=100 kg R-0.25 m -13 g-10 m/s Mass moment of inertia about motor shaft M-M Mass of the elevator cabin Counter mass Radius of the pulley Gear ratio Gravitational acceleration a. Calculate the angular velocity of motor shaft and elevator shaft. b. Find the equivalent mass moment of the system that is lumped at motor shaft. c. Find the total moment acting on the motor shaft (in Newton-meters) in steady state.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.81P: Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center...
icon
Related questions
Question

system modelling and analysıs

QUESTION 1:
The elevator system given in the figure moves up and down
with a velocity of v=1 m/sec. As the elevator starts to move,
it reaches to its steady state angular velocity in 1 seconds.
It is known that all the friction effects within the system are
neglected. The other information related with the system
are given as below:
JM=1.25 kgm?
Jx=1 kgm?
M-400 kg
m=100 kg
Mass moment of inertia about motor shaft M-M
Mass moment of inertia about the elevator shaft K-K
Mass of the elevator cabin
Counter mass
Radius of the pulley
Gear ratio
R=0.25 m
i=13
Gravitational acceleration
g=10 m/s?
a. Calculate the angular velocity of motor shaft and elevator shaft.
b. Find the equivalent mass moment of the system that is lumped at motor shaft.
c. Find the total moment acting on the motor shaft (in Newton-meters) in steady state.
Transcribed Image Text:QUESTION 1: The elevator system given in the figure moves up and down with a velocity of v=1 m/sec. As the elevator starts to move, it reaches to its steady state angular velocity in 1 seconds. It is known that all the friction effects within the system are neglected. The other information related with the system are given as below: JM=1.25 kgm? Jx=1 kgm? M-400 kg m=100 kg Mass moment of inertia about motor shaft M-M Mass moment of inertia about the elevator shaft K-K Mass of the elevator cabin Counter mass Radius of the pulley Gear ratio R=0.25 m i=13 Gravitational acceleration g=10 m/s? a. Calculate the angular velocity of motor shaft and elevator shaft. b. Find the equivalent mass moment of the system that is lumped at motor shaft. c. Find the total moment acting on the motor shaft (in Newton-meters) in steady state.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Quality Assurance, Process Planning, and Quality Control
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
International Edition---engineering Mechanics: St…
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L