Question 13 Use the equation below for this question: N2 (g) + 3 H2 (g) 2NH3 (g) If 0.68 moles of N2 are used to produce 1.00 mol of NH3, what is the percent yield? a 73.5% 93.2% 68.0% d. 87.7%

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Question 13
Use the equation below for this question:
N2 (g) + 3 H2 (g)2NH3 (g)
If 0.68 moles of N2 are used to produce 1.00 mol of NH3, what is the percent yield?
a
73.5%
93.2%
68.0%
d.
87.7%
Transcribed Image Text:Question 13 Use the equation below for this question: N2 (g) + 3 H2 (g)2NH3 (g) If 0.68 moles of N2 are used to produce 1.00 mol of NH3, what is the percent yield? a 73.5% 93.2% 68.0% d. 87.7%
Expert Solution
Step 1

Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%.

If the actual and theoretical yield ​are the same, the percent yield is 100%.

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