Question 32 of 37 Use the following table of bond energies to calculate the molar enthalpy of combustion (in kJ/mol) of acetylene (C2H2) gas in oxygen, based on the following chemical equation: C2H2(g) + 2.502(g) → 2CO2(g) + H2O(g) Single Bond H N H 432 C 411 346 N 386 305 167 459 358 201 142 1 C=C 602 C=O 799 C=C 835 C=0 1072 Multiple 4 Bonds C=N 615 O=0 494 CEN 887 N=N 942 *All values in kJ/mol" 7 +/-

Chemistry & Chemical Reactivity
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ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter23: Carbon: Not Just Another Element
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Question 32 of 37
Use the following table of bond energies to calculate the molar
enthalpy of combustion (in kJ/mol) of acetylene (C2H2) gas in oxygen,
based on the following chemical equation:
C2H2(g) + 2.502(g) → 2CO:(g) + H2O(g)
Single
H
Bond
H
2057 kJ/mol
432
C
411
346
386
305
167
459
358
201
142
1
2
3
C=C
602
C=O
799
C=C
835
C=O
1072
Multiple
Bonds
4
6.
C=N
615
O=O
494
C=N
887
N=N
942
**All values in kJ/mol**
7
8
9.
+/-
CO
LO
Transcribed Image Text:Question 32 of 37 Use the following table of bond energies to calculate the molar enthalpy of combustion (in kJ/mol) of acetylene (C2H2) gas in oxygen, based on the following chemical equation: C2H2(g) + 2.502(g) → 2CO:(g) + H2O(g) Single H Bond H 2057 kJ/mol 432 C 411 346 386 305 167 459 358 201 142 1 2 3 C=C 602 C=O 799 C=C 835 C=O 1072 Multiple Bonds 4 6. C=N 615 O=O 494 C=N 887 N=N 942 **All values in kJ/mol** 7 8 9. +/- CO LO
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