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- 1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the aboveOChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHOStarting from acetone and methanol synthesize isobutylene (CH2=C(CH3)2)
- Give good explanation Asap Thanks calculate the empirical and molecular formula and degrees of saturation. Carbon= 65% Hydrogen= 6.1% Molar mass: 166g/mol what is the empirical formula? molecular formula: c9h__o3 fill in H, what is the molecular formula? degrees of saturation? round to the nearest whole number. is not 6.#B: Methyl acetate has methoxy, -OCH3 as the remaining of the alcohol part in the ester. Isopropyl acetate has isopropoxy, -OCH(CH3)2 as the remaining of the alcohol part in the ester. -OCH(CH3)2 is more electron donating than the methoxy, -OCH3 group due to the presence of two electron-donating -CH3 group in the former. Hence saponification reaction of Isopropyl acetate is much slower than methyl acetate. Hence the rate of saponification of methyl acetate, CH3CCO2CH3 is 50 times greater than that for isopropyl acetate.An unknown alcohol with a molecular formula of C7H14O was oxidized to an aldehyde with HOCl. When an acidic solution of the alcohol was distilled, two alkenes were obtained. The alkene formed in greater yield was determined to be 1-methylcyclohexene. The other alkene formed the original un-known alcohol when treated with BH3/THF followed by H2O2, HO-, and H2O. Identify the unknown alcohol.
- What is the limiting reagent, and their ratios to each other? ( example: 2:3:1) Bromobenzene: 4.5mL Magnesium:1.0g Methyl benzoate:2.5mL Product: 1.82gDraw the structure of the predominant form of CF3CH2OH (pK a = 12.4) at pH = 6.Cembrene, C20H32, is a diterpenoid hydrocarbon isolated from pine resin. Cembrene has a UV absorption at 245 nm, but dihydrocembrene (C20H34), the product of hydrogenation with 1 equivalent of H2, has no UV absorption. On exhaustive hydrogenation, 4 equivalents of H2 react, and octahydrocembrene, C20H40, is produced. On ozonolysis of cembrene, followed by treatment of the ozonide with zinc, four carbonylcontaining products are obtained: Propose a structure for cembrene that is consistent with its formation from geranylgeranyl diphosphate.
- Using molecular models as well as structural drawings, explain why trans-decalin is rigid and cannot ring-flip whereas cis-decalin can easily ring-flip.Each H↔H eclipsing interaction in ethane costs about 4.0 kJ/mol. How many such interactions are percent in cyclopropane? What fraction of the overall 115 kJ/mol (27.5 kcal/mol) strain energy of cyclopropane is due to torsional strain.Nitromethane is reacted with ethyl prop-2-enoate with EtO-Na+, EtOH 3 equivalents to give the product X(C16). X then reacts with H2/Raney Ni to give the product Y(C14), which in turn reacts with Na to give Z (C12). Indicate which products X, Y and Z are.