Question 9 Mr. Muscedere is standing on the top of Herman Secondary School. He drops a ball (starting at rest) from the roof. Mr. Timm (his P.I.C. (partner in crime)) is looking out his window waiting for the ball to pass by. The window he is looking through is 1.6m from bottom to top (window measurement). Mr. Timm notices that it takes the ball 0.20s to pass his window (top of window to bottom). How far above the top of the window did Mr. Muscedere drop it?
Question 9 Mr. Muscedere is standing on the top of Herman Secondary School. He drops a ball (starting at rest) from the roof. Mr. Timm (his P.I.C. (partner in crime)) is looking out his window waiting for the ball to pass by. The window he is looking through is 1.6m from bottom to top (window measurement). Mr. Timm notices that it takes the ball 0.20s to pass his window (top of window to bottom). How far above the top of the window did Mr. Muscedere drop it?
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Vectors
Section: Chapter Questions
Problem 46CP: A pirate has buried his treasure on an island with five trees located at the points (30.0 m, 20.0...
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100%
Please answer question and just send me the paper solutions asap dont type the answer question 9 only
And use the formula that is given dont use any other formula and use 9.81 for acceleration not 9.8 if required please solve it faster asap and dont give wrong answer
Transcribed Image Text:Question 9
Mr. Muscedere is standing on the top of Herman Secondary School. He drops a ball
(starting at rest) from the roof. Mr. Timm (his P.I.C. (partner in crime)) is looking out
his window waiting for the ball to pass by. The window he is looking through is 1.6m
from bottom to top (window measurement). Mr. Timm notices that it takes the ball
0.20s to pass his window (top of window to bottom). How far above the top of the
window did Mr. Muscedere drop it?
Transcribed Image Text:Yos
17
100%
No 0
0%
Equations and Constants
sinA
sinB
sinC
Fnet
a' = b2 + c2 - 2bccosA
= ma
Fr = µFn
C
Ad
Ad = v1At + ½aAť
Ad = v2At - %aAť
%3D
V2 = V1 + aAt
Vav
(v2) = (v1) + 2aAd
ac
472r
4n rf2
v2
Ad = %(v1 + v2)At
g = 9.81
T2
W FAd
W = AE
PE = mgAy
%3D
KE =-mv2
2.
F = kx
Elastic Energy
FAt =
= Ap
p3Dmv
GMm
mearth
5.972 x 1024kg
mmoon
= 7.348 x 1022kg
Fg =72
Nm2
re = 6378 km
Tmoon
1737 m
G = 6.67x10-11
kg?
kg, g.
muroton =
1.67 x 10-27kg
melectron = 9.11 x 10-31kg
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