Answered: Table 2. Series Circuit Data V1 I1 V2…

Table 2. Series Circuit Data V1 I1 V2 I2 Vi+V2 (volts) (mA) (volts) (mA) (volts) (mA) (volts) 6V 16.2 mA 6V 16.2 mA. 6V 16.2 mA ? T=V/R = 6/370 = .0162 Ax 1000 mA/A =16.2

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter33: Alternating Current Circuits

Section: Chapter Questions

Problem 33.4OQ

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Question

R1 is 150 ohms, and R2 is 220 ohms. (150 +220 = 370). In a series circuit, the current is the same across the circuit. The available power storage is 6 volts. The problem I am have is conceptualizing what V1 + V2 equals. I conjecture that the sum would be less than 6 V. I can't say 3 + 3 =6 V, but rather V1 + V2 < 6?

Unless R1=R2, then perhaps 3 + 3 = 6V. However, R1 is 150 ohms, and R2 is 220 ohms.

Complicating issue, if I use an ammeter and voltmeter, these devices may have some internal resistance, so equals becomes < 6 V?

How then do I conceptualize better, V1 + V2, so that maybe it is based on the value of the individual Resistor?

Table 2. Series Circuit Data
V1
I1
V2
I2
Vi+V2
(volts)
(mA)
(volts)
(mA)
(volts)
(mA)
(volts)
6V
16.2 mA
6V
16.2 mA.
6V
16.2 mA ?
T=V/R = 6/370 = .0162 Ax 1000 mA/A =16.2

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