PLEASE ANSWER IN GRECA METHOD PRACTICE EXERCISE 7.5 is the index of refraction of the first medium, n, is the index of refraction of the secon; sin 6, = n, sin 6,Eq 0.whereself.checkWhat are the laws of reflection and refraction?Sample Problem 7.5A ray of light is incident on the surface of a crown glass plate at an angle of 30° with +hnormal. Determine the angle between the refractedand the reflectedгау.гауGiven: 0,=30°n.(from table 7-1)=1.52Ni=1.00"crown glassSolution:Based on the figure, 0=180°–0,'– 0,. Because the angle ofreflection must be equal to the angle of incidence, 0,'=30°. UsingSnell's law in solving for the angle of refraction 02,n, sine, = n, sin 6,(1.00) sin 30° = (1.52) sin 0,aircrown glassplate= 19.2° 19°.Therefore, 0=180° – 30° – 19.2°=130.8°~131°.Practice Exercise 7.5А гayof light passing from water to air is deviated 10° from its original direction. What is the(a) angle of incidence, (b) angle of reflection, and (c) angle of refraction?

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ray of light passing from water to air is deviated 10° from its original direction. a) angle of incidence, (b) angle of reflection, and (c) angle of refraction? A

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter1: The Nature Of Light

Section: Chapter Questions

Problem 53P: Light rays fall normally on the vertical surface of the glass prism (n=1.50)shown below. (a) What is...

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Question

PLEASE ANSWER IN GRECA METHOD PRACTICE EXERCISE 7.5

is the index of refraction of the first medium, n, is the index of refraction of the seco
n; sin 6, = n, sin 6,
Eq 0.
where
self.
check
What are the laws of reflection and refraction?
Sample Problem 7.5
A ray of light is incident on the surface of a crown glass plate at an angle of 30° with +h
normal. Determine the angle between the refracted
and the reflected
гау.
гау
Given: 0,=30°
n.
(from table 7-1)=1.52
Ni=1.00
"crown glass
Solution:
Based on the figure, 0=180°–0,'– 0,. Because the angle of
reflection must be equal to the angle of incidence, 0,'=30°. Using
Snell's law in solving for the angle of refraction 02,
n, sine, = n, sin 6,
(1.00) sin 30° = (1.52) sin 0,
air
crown glass
plate
= 19.2° 19°.
Therefore, 0=180° – 30° – 19.2°=130.8°~131°.
Practice Exercise 7.5
А гay
of light passing from water to air is deviated 10° from its original direction. What is the
(a) angle of incidence, (b) angle of reflection, and (c) angle of refraction?

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