Refer to the circuit below. The nodal equations are given by:201020 VV.320° AT)j20 (1) 52-30° AOA (2 + V -2V2 = 320°- 2V1 + (2 – 2)V2 = 5Z-30*O B. 1290°V + 0.5Z-90°V, = 3.84Z113.2V2 = 1020°Vị -Oc12-90°V + 0.5/90°V, = 3.84/113.2V2 = 10/20°- V +O D. None of the given answersO E. 1290°V; + 0.5/-90°V2 = 3.84Z113.2°V, =10 20°O F. (2 + )V1-2V1 + (2 - j2)V2 = -54-30°2V2 =3220°Aclvate Windov

Refer to the circuit below. The nodal equations are given by: 10220°V 1. V 320° A jin3 52-30° A OA (2 + V - 2V2 = 3220 - 2V1 + (2 - j2)V2 = 5Z-30* %3D O B. 1290°V + 0.5Z-90°V2 = 3.84Z113.2 V2 = 10/20° V1 - %3D Oc12-90°V + 0.5Z90°V2 - VV + = 3.84Z113.2° V2 = 10220° O D. None of the given answers O E. 1290°V1 + 0.5Z-90°V2 - V + = 3.844113.2° V = 10220° OF (2 + V1 - 2V2 = 3220° %3D -2V1 + (2 - j2)V2 = -52-30° %3D

Refer to the circuit below. The nodal equations are given by: 10220°V 1. V 320° A jin3 52-30° A OA (2 + V - 2V2 = 3220 - 2V1 + (2 - j2)V2 = 5Z-30* %3D O B. 1290°V + 0.5Z-90°V2 = 3.84Z113.2 V2 = 10/20° V1 - %3D Oc12-90°V + 0.5Z90°V2 - VV + = 3.84Z113.2° V2 = 10220° O D. None of the given answers O E. 1290°V1 + 0.5Z-90°V2 - V + = 3.844113.2° V = 10220° OF (2 + V1 - 2V2 = 3220° %3D -2V1 + (2 - j2)V2 = -52-30° %3D

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.6MCQ

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