Same question multiple times with answer Refer to the following pedigree.0¹00²"C²-0² 0³ 0¹50O+O²04 08COAccording to this pedigree the chance that individual IV-2 is a heterozyg[Select]10"O"סיים יםיים"סים04012What is the pattern of inheritance for the trait shown in this phylogeny? [Select]SelectY-linkedAutosomal dominant.Autosomal recessiveX-linked dominantAccording to this pedigree the chance that individual IV-7 is a heterozygous carrier is[Select]18°D"0¹0 7148¹513614615If individual IV-7 has three children with individual IV-2 what is the probability (to the nearest hundredth) thatthey would have exactly two affected offspring? [Select] Refer to the following pedigree.|||읽다공모요18056아마Bio¹040 881810우□□□'OO'S8□□'o'sWhat is the pattern of inheritance for the trait shown in this phylogeny? [Select]According to this pedigree the chance that individual IV-2 is a heterozygous carrier is[Select][Select]1 (100%)3/41/41/22/3If individual IV-7 has three children with individual IV-2 what is the probability (to the nearest hundredth) thatthey would have exactly two affected offspring? [Select]hance that individual IV-7 is a heterozygous carrier is

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Description: Same question multiple times with answer Refer to the following pedigree.0¹00²"C²-0² 0³ 0¹50O+O²04 08COAccording to this pedigree the chance that individual IV-2 is a heterozyg[Select]10"O"סיים יםיים"סים04012What is the pattern of inheritance for the

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Refer to the following pedigree. 040² 0'040 3 O+² 00² 6 8 19 Oº 20¹ According to this pedigree the chance that individual IV-2 is a heterozyg [Select] 10 10 18 070³ יסיסייםיםיים יסייםיים סיים What is the pattern of inheritance for the trait shown in this phylogeny? [Select] [Select] Y-linked Autosomal dominant Autosomal recessive X-linked dominant According to this pedigree the chance that individual IV-7 is a heterozygous carrier is [Select] 15

Refer to the following pedigree. 040² 0'040 3 O+² 00² 6 8 19 Oº 20¹ According to this pedigree the chance that individual IV-2 is a heterozyg [Select] 10 10 18 070³ יסיסייםיםיים יסייםיים סיים What is the pattern of inheritance for the trait shown in this phylogeny? [Select] [Select] Y-linked Autosomal dominant Autosomal recessive X-linked dominant According to this pedigree the chance that individual IV-7 is a heterozygous carrier is [Select] 15

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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. A true-breeding strain of Virginia tobacco has dominantalleles determining leaf morphology (M), leaf color(C), and leaf size (S). A Carolina strain is homozygousfor the recessive alleles of these three genes. Thesegenes are found on the same chromosome as follows:M C S6 m.u. 17 m.u.An F1 hybrid between the two strains is now backcrossedto the Carolina strain. Assuming no interference:a. What proportion of the backcross progeny willresemble the Virginia strain for all three traits?b. What proportion of the backcross progeny willresemble the Carolina strain for all three traits?c. What proportion of the backcross progeny will havethe leaf morphology and leaf size of the Virginiastrain but the leaf color of the Carolina strain?d. What proportion of the backcross progeny will havethe leaf morphology and leaf color of the Virginiastrain but the leaf size of the Carolina strain?
In the 1800s, a man with dwarfism who lived in Utah produced a large number of descendants: 22 children, 49 grandchildren, and 250 greatgrandchildren (see the illustration of a family pedigree to the right), many of whom also exhibited dwarfism (F. F. Stephens. 1943. Journal of Heredity 34:229–235). The type of dwarfism found in this family is called Schmid-type metaphyseal chondrodysplasia, although it was originally thought to be achondroplastic dwarfism. Among the families of this kindred, dwarfism appeared only in members who had one parent with dwarfism. When one parent exhibited dwarfism, the following numbers of children were produced. Q. Use chi-square tests to determine if the numbers of children with each phenotype in family C (1 with normal stature, 6 with dwarfism) and in family D (6 with normal stature, 2 with dwarfism) are significantlydifferent from the numbers expected on the basis of your proposed mode of inheritance. How would you explain these deviations from the…
From the pedigree shown here, answer the following questions with regard to individual VII-1. A. Who are the common ancestors of her parents? B. What is the inbreeding coefficient for this individual?
The distance between two molecular markers that are linked alongthe same chromosome can be determined by analyzing the outcomesof crosses. This can be done in humans by analyzing a family’spedigree. However, the accuracy of linkage mappingwith human pedigrees is fairly limited because the number of people in mostfamilies is relatively small. As an alternative, researchers can analyze a population of sperm, produced from a single male, and computelinkage distance in this manner. As an example, let’s suppose a maleis heterozygous for two polymorphic STSs. STS-1 exists in two sizes:234 bp and 198 bp. STS-2 also exists in two sizes: 423 bp and 322bp. A sample of sperm was collected from this man, and individualsperm were placed into 40 separate tubes. In other words, there wasone sperm in each tube. Believe it or not, PCR is sensitive enough toallow analysis of DNA in a single sperm! Into each of the 40 tubeswere added the primers that amplify STS-1 and STS-2, and then thesamples were…
From a series of two-point crosses, the following mapdistances were obtained for the syntenic genes A, B,C, and D in peas:B ↔ C 23 m.u.A ↔ C 15 m.u.C ↔ D 14 m.u.A ↔ B 12 m.u.B ↔ D 11 m.u.A ↔ D 1 m.u.Chi-square analysis cannot reject the null hypothesis of no linkage for gene E with any of theother four genes.a. Draw a cross scheme that would allow you todetermine the B ↔ C map distance.b. Diagram the best genetic map that can be assembled from this data set.c. Explain any inconsistencies or unknown features inyour map.d. What additional experiments would allow you toresolve these inconsistencies or ambiguities?
Given the following pedigree (note that C7C, M4C, N2X, H6C, G9X, J1C, B8X, and P2X are the names of animals):
E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings (E. W. Lindstrom. 1921. Genetics 6:91–110). a. Give the genotypes for the green, virescent-white, and yellow progeny. b. Explain how color is determined in these seedlings. c. Is there epistasis among the genes that determine color in the corn seedlings? If so, which gene is epistatic and which is hypostatic?
2. Genes a and b are 21 m.u. apart when mapped inhighly inbred strain 1 of corn and 21 m.u. apart whenmapped in highly inbred strain 2. But when the distance is mapped by testcrossing the F1 progeny of across between strains 1 and 2, the two genes are only1.5 m.u. apart. What arrangement of genes a and band any potential rearrangement breakpoints couldexplain these results?
Assume that there is complete interference in the Lf-W region. The cross between the triple heterozygote (Lf J W/ lf j w) and a triple homozygous recessive produced 350 progenies. Give the frequency of each specific progeny type:a. with crossover in the Lf-J and J-W regionsb. with crossover in the Lf-J regionc. with crossover in the J-W regiond. without crossover in the Lf-W region
Neurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe list
Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progeny