[References]otA sample of calcium metal with a mass of 2.06 g was reacted with excess oxygen. The following equation represents the reaction that took place:ot2Ca(s) + O2 (g) →2CaO(s)The isolated product (CaO) weighed 2.25 g. What was the percentage yield of the reaction?ototPercentage yieldot

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[References] A sample of calcium metal with a mass of 2.06 g was reacted with excess oxygen. The following equation represents the reaction that took place: 2Ca(s) + O2(g)→ 2CaO(s) The isolated product (CaO) weighed 2.25 g. What was the percentage yield of the reaction? Percentage yield :

[References] A sample of calcium metal with a mass of 2.06 g was reacted with excess oxygen. The following equation represents the reaction that took place: 2Ca(s) + O2(g)→ 2CaO(s) The isolated product (CaO) weighed 2.25 g. What was the percentage yield of the reaction? Percentage yield :

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter5: Chemical Reactions

Section: Chapter Questions

Problem 5.58E

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

[References]
ot
A sample of calcium metal with a mass of 2.06 g was reacted with excess oxygen. The following equation represents the reaction that took place:
ot
2Ca(s) + O2 (g) →
2CaO(s)
The isolated product (CaO) weighed 2.25 g. What was the percentage yield of the reaction?
ot
ot
Percentage yield
ot

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