Researchers at the National Cancer Institute released the results of a study that examined the effect of weed-killing herbicides on house pets. Dogs were examined for the presence of malignant lymphoma. The data gathered is as follows: Sample Size Number with Lymphoma p Group Home used weed-killer Home did not use weed-killer 827 473 0.572 130 19 0.146 Construct a 95% confidence interval for the difference of the true proportions of exposed dogs that develop lymphoma and unexposed dogs that develop lymphoma. a) Can we use our confidence interval in part a) to conclude that the true proportion of exposed dogs that develon lymphoma ie high
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- In a study of academic procrastination, the authors of a paper reported that for a sample of 431 undergraduate students at a midsize public university preparing for a final exam in an introductory psychology course, the mean time spent studying for the exam was 7.54 hours and the standard deviation of study times was 3.90 hours. For purposes of this exercise, assume that it is reasonable to regard this sample as representative of students taking introductory psychology at this university. (a) Construct a 95% confidence interval to estimate ?, the mean time spent studying for the final exam for students taking introductory psychology at this university. (Round your answers to three decimal places.)( , )(b) The paper also gave the following sample statistics for the percentage of study time that occurred in the 24 hours prior to the exam. n = 431 x = 43.88 s = 21.66 Construct a 90% confidence interval for the mean percentage of study time that occurs in the 24 hours prior…A healthcare information company is interested in estimating the average charge for a standard patient visit to a chiropractor in Maryland, after applying the discount negotiated with a large HMO plan. Data is collected from 16 randomly selected chiropractic practices in Maryland, and the following are some summary statistics:- Mean charge: 25.50 USD- SD of charges: 2.10 USDAssuming the charge data is normally distributed for all chiropractic practices in Maryland, estimate a 95% confidence interval for the mean amount charged by Maryland chiropractors (t (15, 0.05) = 2.13):A study of 420,035 cell phone users found that 0.0326% of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0331% for those not using cell phones. Complete parts (a) and (b).Question content area bottomPart 1a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.enter your response here%<p<enter your response here%(Do not round until the final answer. Then round to three decimal places as needed.)Part 2b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not?A.Yes, because 0.0331% is not included in the confidence interval.B.Yes, because 0.0331% is included in the confidence interval.C.No, because 0.0331% is included in the confidence interval.D.No,…
- A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…In a study of a proposed treatment for diabetes prevention, 339 people under the age of 20 who were thought to be at high risk of developing type I diabetes were assigned at random to two groups. One group received twice-daily injections of a low dose of insulin. The other group (the control) did not receive any insulin, but was closely monitored. Summary data are given below. Group n NumberDevelopingDiabetes Insulin 169 41 Control 170 40 (a) Use the given data to construct a 90% confidence interval for the difference in the proportion that develop diabetes for the control group and the insulin group. (Use ?Insulin − ?Control. Round your answers to three decimal places.)A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them said they got along “very well” with their parents. Use this information to construct a 95% confidence interval estimate of the percentage of all U.S. teenagers that get along “very well” with their parents.
- A marketing study with a random sample of 400 results in 160 subjects reacting positively to the proposed product. Determine the 95% confidence interval for the population proportion.Suppose that a safety group surveyed 1,100 drivers. Among those surveyed, 65% said that careless or aggressive driving was the biggest threat on the road, and 25% said that cell phone usage by other drivers was the driving behavior that annoyed them the most. Based on these data and assuming that the sample was a simple random sample, construct and interpret a 95% confidence interval estimate for the true proportion in the population of all drivers who are annoyed by cell phone users. The confidence interval estimate is ??––––––??> (Round to three decimal places as needed. Use ascending order.) Interpret the confidence interval estimate. A. There is a 0.95 probability that the population proportion of drivers who are annoyed by cell phone users is in the interval. B. There is 95% confidence that the population proportion of drivers who are annoyed by cell phone users is in the interval. C. There is 95% confidence that the population proportion…An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (b) Given the method used by the environmental science teacher to collect the responses, explain how bias might have been introduced and describe how the bias might affect the point estimate of the proportion of all students at the school who would respond yes to the question.
- An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (a) How many students were in the sample selected by the environmental science teacher?An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (c) The statistics teacher at the high school was concerned about the potential bias in the survey. To obtain a potentially less biased estimate of the proportion, the statistics teacher used an alternate method for collecting student responses. A random sample of 300 students was selected, and each student was given the following instructions on how to respond to the question. • In private, flip a fair coin. • If heads, you…