Residents of a Valentine, a small city in Nebraska, meet for a city council meeting once a week. Meetings are supposed to last no hore than 3 hours. However, many residents are complaining that the average meeting is significantly longer than 3 hours. In order to test this, the meeting lengths of the last 15 meetings were recorded in minutes: 147.0, 155.4, 159.6, 162.6, 163.8, 165.0, 167.4, 169.2, 172.2, 172.8, 172.8, 175.8, 175.8, 196.8, 201.6. Using this data, test the null hypothesis at the alpha = 0.1 level that the mean length of city council meetings is equal to 3 hours versus the alternative that the average meeting length is greater than 3 hours. Assume that the distribution of meeting lengths is normal. What is the p-value and conclusion of this test? p-value = 0.046; Fail to reject the null hypothesis %3D p-value = 0.046; Reject the null hypothesis p-value = 0.9897; Fail to reject the null hypothesis p-value = 0.9897; Reject the null hypothesis %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 67E
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Oshg/cki5esn6w00003a5ttq4snsd6
E VIEW LIST
Residents of a Valentine, a small city in Nebraska, meet for a city council
meeting once a week. Meetings are supposed to last no hore than 3 hours.
However, many residents are complaining that the average meeting is
significantly longer than 3 hours. In order to test this, the meeting lengths
of the last 15 meetings were recorded in minutes: 147.0, 155.4, 159.6,
162.6, 163.8, 165.0, 167.4, 169.2, 172.2, 172.8, 172.8, 175.8, 175.8,
196.8, 201.6. Using this data, test the null hypothesis at the alpha = 0.1
level that the mean length of city council meetings is equal to 3 hours
versus the alternative that the average meeting length is greater than 3
hours. Assume that the distribution of meeting lengths is normal. What is
the p-value and conclusion of this test?
p-value = 0.046; Fail to reject the null hypothesis
p-value = 0.046; Reject the null hypothesis
p-value = 0.9897; Fail to reject the null hypothesis
p-value = 0.9897; Reject the null hypothesis
NEXT
Transcribed Image Text:Oshg/cki5esn6w00003a5ttq4snsd6 E VIEW LIST Residents of a Valentine, a small city in Nebraska, meet for a city council meeting once a week. Meetings are supposed to last no hore than 3 hours. However, many residents are complaining that the average meeting is significantly longer than 3 hours. In order to test this, the meeting lengths of the last 15 meetings were recorded in minutes: 147.0, 155.4, 159.6, 162.6, 163.8, 165.0, 167.4, 169.2, 172.2, 172.8, 172.8, 175.8, 175.8, 196.8, 201.6. Using this data, test the null hypothesis at the alpha = 0.1 level that the mean length of city council meetings is equal to 3 hours versus the alternative that the average meeting length is greater than 3 hours. Assume that the distribution of meeting lengths is normal. What is the p-value and conclusion of this test? p-value = 0.046; Fail to reject the null hypothesis p-value = 0.046; Reject the null hypothesis p-value = 0.9897; Fail to reject the null hypothesis p-value = 0.9897; Reject the null hypothesis NEXT
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