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Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 99 of the 113 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P12 P2 H4: P1 # P2 O B. Ho: P1 # p2 H1: P1 = P2 O C. Ho: P1 = P2 H: P1 # P2 O D. Ho: P1 = P2 H1: P1 > P2 O E. Ho: P1 SP2 H4: P1 #P2 O F. Ho: P1 = P2 H1: P1

Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 99 of the 113 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P12 P2 H4: P1 # P2 O B. Ho: P1 # p2 H1: P1 = P2 O C. Ho: P1 = P2 H: P1 # P2 O D. Ho: P1 = P2 H1: P1 > P2 O E. Ho: P1 SP2 H4: P1 #P2 O F. Ho: P1 = P2 H1: P1

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 6E: List the sample space of each experiment. Tossing three coins
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Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 99 of the 113 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 2 P2 H1: P1 # P2 B. Ho: P1 + P2 O C. Ho: P1 = P2 H1: P1 = P2 H: P1 # P2 F. Ho: P1 = P2 E. Ho: P1 sP2 H4: P1 # P2 D. Ho: P1 = P2 H1: P1 > P2 H4: P1 <P2 Identify the test statistic. Z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is the significance level of a = 0.05, so the null hypothesis. There sufficient evidence to support the claim that echinacea treatment has an effect. b. Test the claim by constructing an appropriate confidence interval. The 95% confidence interval isO< (P1 - P2) <U. (Round to three decimal places as needed.) What is the conclusion based on the confidence interval? Because the confidence interval limits 0, there appear to be a significant difference between the two proportions. There evidence to support the claim that echinacea treatment has an effect.
Transcribed Image Text:Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 99 of the 113 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 2 P2 H1: P1 # P2 B. Ho: P1 + P2 O C. Ho: P1 = P2 H1: P1 = P2 H: P1 # P2 F. Ho: P1 = P2 E. Ho: P1 sP2 H4: P1 # P2 D. Ho: P1 = P2 H1: P1 > P2 H4: P1 <P2 Identify the test statistic. Z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is the significance level of a = 0.05, so the null hypothesis. There sufficient evidence to support the claim that echinacea treatment has an effect. b. Test the claim by constructing an appropriate confidence interval. The 95% confidence interval isO< (P1 - P2) <U. (Round to three decimal places as needed.) What is the conclusion based on the confidence interval? Because the confidence interval limits 0, there appear to be a significant difference between the two proportions. There evidence to support the claim that echinacea treatment has an effect.
c. Based on the results, does echinacea appear to have any effect on the infection rate? A. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it lowers the infection rate. B. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it increases the infection rate. C. Echinacea does not appear to have a significant effect on the infection rate. O D. The results are inconclusive.
Transcribed Image Text:c. Based on the results, does echinacea appear to have any effect on the infection rate? A. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it lowers the infection rate. B. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it increases the infection rate. C. Echinacea does not appear to have a significant effect on the infection rate. O D. The results are inconclusive.
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