РоPay2 - yı(h)Pressure p Tp + pgyi'`Pa + pgy2 The height difference is 760 mm, and the gauge pressure is 5,218.92 Pa. Find the density of the liquid inside themanometer. Note: Air pressure = 101, 325 PaPo = Pavy2 - yı(h)Pressure py2

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Ро Pa y2 - Yı (h) Pressure p y2 p + pgyi *Pa + pgy2

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter5: Analysis Of Convection Heat Transfer

Section: Chapter Questions

Problem 5.5P: Evaluate the dimensionless groups hcD/k,UD/, and cp/k for water, n-butyl alcohol, mercury, hydrogen,...

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Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

Question

Ро
Pa
y2 - yı
(h)
Pressure p T
p + pgyi'
`Pa + pgy2

The height difference is 760 mm, and the gauge pressure is 5,218.92 Pa. Find the density of the liquid inside the
manometer. Note: Air pressure = 101, 325 Pa
Po = Pav
y2 - yı
(h)
Pressure p
y2

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