Run a regression analysis on the following bivariate set of data with y as the response variable. x y 20.9 45.3 19.9 50.1 28.2 18.3 21.3 50.3 18.5 39.1 42.3 -9.4 5 73.7 34.7 46.4 25.9 26.3 26.3 50.3 38.2 21.8 6.7 81.1 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r² = % Based on the data, calculate the regression line (each value to three decimal places) y = x + Predict what value (on average) for the response variable will be obtained from a value of 41.3 as the explanatory variable. What is the predicted response value? (Report answer accurate to one decimal place.) y =
Run a
| x | y |
|---|---|
| 20.9 | 45.3 |
| 19.9 | 50.1 |
| 28.2 | 18.3 |
| 21.3 | 50.3 |
| 18.5 | 39.1 |
| 42.3 | -9.4 |
| 5 | 73.7 |
| 34.7 | 46.4 |
| 25.9 | 26.3 |
| 26.3 | 50.3 |
| 38.2 | 21.8 |
| 6.7 | 81.1 |
Find the
r =
What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)
r² = %
Based on the data, calculate the regression line (each value to three decimal places)
y = x +
Predict what value (on average) for the response variable will be obtained from a value of 41.3 as the explanatory variable.
What is the predicted response value? (Report answer accurate to one decimal place.)
y =
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