(S208 2-), M In rate vs In [S208 2-] at constant [1-] In [S208 2-) Runs Reaction time, s Rate, M/s In rate Slope Intercept r2 value Rate order Rounded off Rate orders are typically whole numbers or fractions Runs Rate constant 1 2a 3 4 Average
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A: Since you have posted multiple questions, we are entitled to answer the first only.
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Q: In rate vs In [S208 2-] at constant [I-] In [S208 2-1 Reaction time, s Rate, M/s 0.00000 0.00000…
A: Table to be completed
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Q: the data provided. 2NO(g) + O2(g) - 2NO2(g) [NO] [02] Rate 0.030 0.0055 8.55 x 103 0.030 0.0110…
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Q: 40.) Two isomers (A and B) of a given compound dimerize as follows ALA = k1[A] At 2 A A2 Rate = -…
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- NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,kWhich one of the following statement is not true regarding the material balance equation: AR = IR – OR + GR Group of answer choices OR is the Output Rate, it represents the amount of mass leaving the process boundary AR is the Accumulation Rate, it’s 0 under steady-state conditions IR is the Input Rate, and its unit should be mass per time GR is the Generation Rate and it can only be positive, as indicated by the plus signPLS HELP VERY URGENT Q15
- The company performs accelerated ageing studies in which a suspension of D is stored at different temperatures. They obtain the degradation rate constants in the table below. Calculate the rate constant for degradation at 25 ºC. (45 % of marks) T / ºC k / d-1 40 0.28 50 0.56The first-order degradation rate constant k was determined to be 0.0125/day for contaminant A and 0.0030/day for contaminant B in a soil. Calculate the half-life T1/2 and the 95% dissipation time for these contaminants in the soil. Compare the persistence between the two contaminants.An enzyme with Km value of 15.75 M and Vm is 30 micromole/L.min is used in a batch reactor. Calculate the time of reaction required for 88% substrate conversion where the initial substrate concentration was 160 M.
- a) Determine kcat (in units of sec-1) for a particular enzyme, given the following information: Vo = 144 mmol/min; [S] = 2 mM; Km = 0.5 mM; Enzyme Molecular weight = 40,000 micrograms/micromole; 8 micrograms of enzyme used in assay generating this data. b) In general, explain how the total enzyme concentration affects turnover number and Vmax?Benzene is dissolved at a constant initial concentration of 350 mg/l and is contained within a landfill in leachate water above bottom liner of the landfill system. It starts to diffuse through the liner at time t = 0. Using Equation Ci (x,t) = Co erfc x/ 2(D*t)0.5 related narrative, and (error function table), calculate the concentration of benzene at its breakthrough location as it diffuses through a 1.5 meter thick liner (x=1.5 meters represents breakthrough location where liner fails of contaminant is released), after 50 years. Assume D = 10-5 m2/sec (diffusion coefficient in free standing water) and w = 0.7 (coefficient of tortuousity). Clearly present your assumptions and your value of erf, Select the answer range which best fits the answer you calculate. Group of answer choices 315 to 350 mg/l My answer is not in the range of any of the choices my answer. 215 to 314 mg/l 175 to 200 mg/l 370 to 400 mg/lCHEMISTRY RATE WILL BE GIVEN! NO LONG EXPLANATION NEEDED. PLEASE ANSWR 22-24