(c) Compute the P-value. Round the answer to at least four decimal places.P-value = 1.355Part: 3/5Part 4 of 5(d) Determine whether to reject Ho.At the a=0.10 level, rejectPart: 4/5Part 5 of 53▼the null hypothesis Ho.X3(e) State a conclusion.At the α = 0.10 level of significance, there (Choose one) enough evidence to conclude that the percentage of technology companies that have Twitteraccounts differs from 73%, Tweet tweet: An article reported that 73% of companies have Twitter accounts. An economist thinks the percentage is different at technology companies. Shesamples 70 technology companies and finds that 44 of them have Twitter accounts. Can she conclude that the percentage of technology companies that haveTwitter accounts differs from 73%? Use the a=0.10 level of significance and the P-value method with the TI-84 Plus calculator.Part 1 of 5(a) State the appropriate null and alternate hypotheses.Ho: p = 0.73H₁: p = 0.73This hypothesis test is a two-tailed ▼test.Part 2 of 5z = -0.01Part: 2/5Part 3 of 5OOŚ00X(b) Compute the value of the test statistic. Round the answer to two decimal places.Рローロ(c) Compute the P-value. Round the answer to at least four decimal places.3Español

The hypothesized proportion is 0.73.

Answered: samples 70 technology companies and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Match the p-values with the appropriate conclusion: I. 0.00001 II. 0.0189 III. 0.0611 IV. 0.4234(a) The evidence against the null hypothesis is significant, but only at the 10% level. (b) The evidence against the null and in favor of the alternative is very strong. (c) There is not enough evidence to reject the null hypothesis, even at the 10% level. (d) The result is significant at a 5% level but not at a 1% level.
Data from the 2014 General Social Survey (GSS) show that out of n=1,606 adult respondents, the proportion who reported having voted for Barack Obama in the 2008 presidential election was 0.61 Q: If I calculate a z test static of 4.84, and my alpha = 0.05, what decision should I make about the hypothesis? (Calculate the p-value for a 2-sided test to make your decision.) Options: A: fail to reject the null hypothesis that the proportion of American adults who voted for Obama in 2008 was 0.55 B: reject the null hypothesis that the proportion of American adults who voted for Obama in 2008 was 0.55 C: Reject the alternative hypothesis that the proportion of American Adults who voted for Obama in 2008 was not equal to 0.55 D: Fail to reject the alternative hypothesis that the proportion of American adults who voted for Obama in 2008 was not equal to 0.55
In a local community past data shows that 17% of the residents own a skateboard, and the city is considering building more green lanes to accommodate these skate boarders as a recent survey showed that 63 out of 270 people supported the concept of more green lanes on the city's streets. a) State the null and alternative hypothesis. b) Find a Z and P-value, and state your conclusion using alpha = 5% c) Re-do part (b) using the Chi-square test, also stating your conclusion using alpha = 5%
.A sample of 9 measurements, randomly selected from a normally distributed population, resulted in x= 2.6, and s= 0.9 Conduct a hypothesis test to verify the claim that the population mean is greater than 2.5 . Use a=.05
Dr. Chapman conducted an experiment in which participants watched paint dry for 30 minutes twice, once being paid $1 and once being paid $30. When comparing the samples, he calculated t = 3.57. He assumed α = .01 with df = 5, so the tcv = ±4.032. Because the calculated value was: A. greater than the critical value, Dr. Chapman can reject the null hypothesis. B. greater than the critical value, Dr. Chapman failed to reject the null hypothesis. C. less than the critical value, Dr. Chapman failed to reject the null hypothesis. D. less than the critical value, Dr. Chapman can reject the null hypothesis.
In a previous Paul, 44% of adults and children under the age of 18 reported that their family eat dinner together seven nights a week... use technology to find the P value. P value =_. (round to three decimal places as needed.) should one reject the null hypothesis? or should one not reject the null hypothesis?
A random sample of 430 observations produced a sample proportion equal to 0.39. Find the critical and observed values of z for the following test of hypotheses using α=0.025. H0: p=0.30 versus H1: p≠0.30. Round your answers to two decimal places.
Arandom sample of 450 observations produced a sample proportion equal to 0.38. Find the critical and observed values of z for the following test of hypotheses using alpha = 0.025 . H 0 :p=0.30 versus H 1 :p not equal to 0.30
A hypothesis test was conducted, at α = 0.05, to determine whether a certain chemical compound lasts longer than 30 seconds under a certain specified condition. The hypotheses used were: H0: µ = 30 Ha: µ > 30 A sample mean of 37.4 seconds was obtained from a sample of size n = 80. All statistical assumptions were met, and a p-value of p = 0.0089 was obtained. Which of the following is correct? a) If the null hypothesis were in reality true that the population mean was equal to 30, then the probability of observing a sample mean of 37.4 seconds from a sample of size n = 80 would be only .0089. b) If the null hypothesis were in reality false that the population mean was equal to 30, then the probability of observing a sample mean of 37.4 seconds (or less) from a sample of size n = 80 would be only .0089. c) If the null hypothesis were in reality true that the population mean was equal to 30, then the probability of observing a sample mean of 37.4 seconds (or greater) from…
A researcher who wants to know whether the proportion of male births in a hospital is different from the established baseline of 51.07%, would like to test the following hypotheses: Ho:P = 0.51 vs. Ha :P = does not equal 0.51 a) Is the alternative hypothesis upper tail, lower tail, or two tailed? b) What do you conclude if the test results p-value of 0.03 at alpha value = 5% c) What do you conclude if the test results p-value of 0.08 at alpha value = 10%
Assume we wanted to show that the true proportion of virginica iris seeds that fail to germinate is less than 20%. Let's say we tested at an alpha of 0.05, and found a p-vale of 0.082. Which of the following would be an appropriate conclusion and interpretation? A) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state we have insufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. B) With an alpha of 0.05, and a p-value of 0.0082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. C) With an alpha of 0.05, and a p-value of 0.082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. D) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state…
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…

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